Numerical integration over a variable

Hello all
I have a function as given below and i want to integrate it over a variable but i am getting answer "V1=0".
However V1 can not be equal to "0" .
What is wrong?
Vb=0.450; dz=1e-10;
Ltot = 20e-9;
z=-Ltot/2:dz:Ltot/2;
L = 10e-9; a=2e-9; x=-L/2:dz/2:L/2;
f=Vb.*real(x./sqrt(a^2-(x-z).^2));
V1=trapz(~isnan(f),x)
V1 = 0

 Respuesta aceptada

Walter Roberson
Walter Roberson el 10 de Nov. de 2021

0 votos

trapz(x, y) is the syntax. If isnan is either always true or is never true for f then the "x" coordinates would all be the same (all true or all false, and in that case, the output would be mean() of the "y" coordinates. But your "y" coordinates are your x variable and that happens to be symmetrical around zero, so the mean is zero and your result is 0

Más respuestas (0)

Categorías

Preguntada:

el 10 de Nov. de 2021

Respondida:

el 10 de Nov. de 2021

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by