How to change alternate four consecutive elements into zeros in an array of ones?

I created array of ones [1 1 1 1 1 1 1 1 ...] (size 64)

Now i to convert the alternate four consecutive elements into zeros.

eg: [1 1 1 1 0 0 0 0 1 1 1 1 0 0 0 0 1 1 1 1....]

How do i do this?

Answer 1

[Image Analyst]

Assuming it's not your homework (in which case you can't turn it in or risk trouble), here are a few ways:

% Method 1
v = ones(1, 64);
v(5:8:end) = 0;
v(6:8:end) = 0;
v(7:8:end) = 0;
v(8:8:end) = 0
% Method 2
v = ones(1, 64);
v2 = reshape(v, [], 8);
v2(:, 5:8) = 0;
v = reshape(v2', 1, [])
% Method 3
v = ones(1, 64);
v2 = reshape(v, [], 8);
v2(5:8, :) = 0;
v = reshape(v2, 1, [])

[Samson David Puthenpeedika]

Thankyou . Actually can we use for loop for the same ? If yes then how ?

[Image Analyst]

@Samson David Puthenpeedika I hope you at least gave it a try since it's only 3 lines of code. Here is how I did it

% Method 4
v = ones(1, 64);
for k = 5 : 8 : length(v)
    v(k:k+3) = 0;
end
v

v = 1×64

1 1 1 1 0 0 0 0 1 1 1 1 0 0 0 0 1 1 1 1 0 0 0 0 1 1 1 1 0 0

If my answer solved it (or solved it 4 times) then could you please click the "Accept this Answer" link? Thanks in advance.

[Samson David Puthenpeedika]

Thankyou so much sir