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mean of matrix elements

Asked by john creighton on 15 Oct 2014
Latest activity Commented on by john creighton on 16 Oct 2014
hey all. i have a 5760x1 matrix. i need to find the average of the first 10 elements, remove the 10 elements and replave with the averaged number, find the average of the next 10 elements, remove those 10 elements and replace with average and so on.... could anyone give me an insight as to how to do this? much appreciated john

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4 Answers

Sean de Wolski
Answer by Sean de Wolski
on 15 Oct 2014
 Accepted Answer

B = mean(reshape(x,10,[]))'
Where x is your original column vector and B is the mean of every 10x1 chunk

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Answer by Andrew Reibold on 15 Oct 2014
Edited by Andrew Reibold on 15 Oct 2014

myMatrix = rand(5760,1)
for jj = 1:576
moving_avg(jj,1) = mean(myMatrix(jj*10-9:jj*10));
end
Will make a matrix called 'moving_avg' where each point represents the average of each set of 10 points.
Is that what you wanted? It will be 1/10 the size.

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Its very easy to replace every single point with the average too if thats what you need. (Same size, but every set of 10 numbers are all the same averaged number.)

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Andrei Bobrov
Answer by Andrei Bobrov
on 16 Oct 2014

I want have 'vote' too!
out = accumarray(ceil((1:numel(x))'/10),x(:),[],@mean);

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Sean de Wolski
on 16 Oct 2014
b=blkproc(rand(5760,1),[10,1],@mean)
I can't think of a solution shorter than my reshape one in terms of Code Golf?
haha. yours works too...so well deserved 'vote' :)

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Answer by john creighton on 16 Oct 2014

Both answers worked perfectly. Thanks guys. sorry can only accept one answer lol

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Sean de Wolski
on 16 Oct 2014
You can vote too :)

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