How can I use a logical array to remove and replace values in a corresponding data array?

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I have an array A (1280 x 1024) that has some rogue values that I want to remove and replace with a linear interpolation of the two nearest neighbouring elements (that are not rogue) in the column. (I call them 'rogue' rather than outliers because the values can appear ok statistically.)
I have a logical array TF (1280 x 1024) whose elements are true if the corresponding element in A is rogue.
How do I do create the corrected array, B?
Example (5 x 3 array shown for simplicity):
TF = 5×3 logical array
0 0 0
0 0 0
0 0 1
0 1 0
0 0 0
A = 5×3
54 46 32
48 60 50
50 51 59
51 49 48
45 55 66
I want the output to be:
B = 5×3
54 46 32
48 60 50
50 51 49
51 53 48
45 55 66
The function 'filloutliers(A,'linear')' is close but that function seems to generate its own TF array whereas I want to implement the TF array that I already have.
I'm using the R2020a version of Matlab. Thank you.

Respuesta aceptada

Star Strider
Star Strider el 17 de Nov. de 2021
See if the fillmissing funciton produces the desired result —
TF = [0 0 0
0 0 0
0 0 1
0 1 0
0 0 0];
TF = TF == 1; % Create Logical Array From Numeric Array
A = [54 46 32
48 60 50
50 51 59
51 49 48
45 55 66];
A(TF) = NaN; % Set 'TF' Entries To 'NaN'
A = fillmissing(A, 'nearest')
A = 5×3
54 46 32 48 60 50 50 51 48 51 55 48 45 55 66
.
  2 comentarios
Steve Francis
Steve Francis el 17 de Nov. de 2021
Thanks for your answer, Star Strider. This works if I replace 'nearest' with Matt's suggestion of 'linear'.
Appreciate the comments in the code.

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Más respuestas (1)

Matt J
Matt J el 17 de Nov. de 2021
Editada: Matt J el 17 de Nov. de 2021
Perhaps as follows,
A(TF)=nan;
A=fillmissing(A,'linear');

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