plot stream over two spheres
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A =[ -4.7107
0.0012
-0.0056
0.0132
-0.0253
0.0435
-0.0689
0.1031
-0.1473
0.2040
-0.2737
0.3607
-0.4647
0.5927
-0.7425
0.9265
-1.1387
1.4014
-1.7014
2.0810
-2.5114
3.0805
-3.7224
4.6475
-5.6872
7.5039
-9.5388
16.4146
-25.4535
14.3236];
B=[ -3.3794
0.0005
-0.0009
0.0006
-0.0003
0.0001
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000];
C=[ 6.8417
-0.0007
0.0007
-0.0003
0.0001
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000];
D=[ -4.7100
-0.0012
0.0058
-0.0132
0.0253
-0.0435
0.0689
-0.1032
0.1473
-0.2040
0.2737
-0.3608
0.4648
-0.5928
0.7426
-0.9266
1.1388
-1.4016
1.7016
-2.0813
2.5118
-3.0810
3.7230
-4.6482
5.6881
-7.5050
9.5403
-16.4171
25.4574
-14.3258];
E=[ -3.3789
-0.0005
0.0009
-0.0006
0.0003
-0.0001
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000];
F=[ 6.8407
0.0007
-0.0008
0.0003
-0.0001
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000];
a = 1 ; %RADIUS
L=.1;
dd=4;
kappa=1;gam=0.3;arh=1; %a2=1;u2=1;beta1=beta2=1
al=kappa.*(2+kappa)./(gam.*(1+kappa));
alpha1=real(((al.^2+arh.^2)./2+((al.^2+arh.^2).^2-(2.*kappa.*arh.^2./gam).^(1./2))./2).^(1./2));
alpha2=real(((al.^2+arh.^2)./2-((al.^2+arh.^2).^2-(2.*kappa.*arh.^2./gam).^(1./2))./2).^(1./2));
c =-a/L;
b =a/L;
m =a*100; % NUMBER OF INTERVALS
[x,y]=meshgrid([c+dd:(b-c)/m:b],[c:(b-c)/m:b]);
[I, J]=find(sqrt(x.^2+y.^2)<(a-.1));
if ~isempty(I)
x(I,J) = 0; y(I,J) = 0;
end
r=sqrt(x.^2+y.^2);
t=atan2(y,x);
r2=sqrt(r.^2+dd.^2-2.*r.*dd.*cos(t));
zet=(r.^2-r2.^2-dd.^2)./(2.*r2.*dd);
%for i1=1:length(x);
% for k1=1:length(x);
% if sqrt(x(i1,k1).^2+y(i1,k1).^2)>1./L;
% r(i1,k1)=0;r2(i1,k1)=0;
% end
% end
%end
warning off
qr1=0;
for i=2:7
Ai=A(i-1);Bi=B(i-1);Ci=C(i-1);Di=D(i-1);Ei=E(i-1);Fi=F(i-1);
qr1=qr1-(Ai.*r.^(-i-1)+r.^(-3./2).*besselk(i-1./2,r.*alpha1).*Bi+r.^(-3./2).*besselk(i-1./2,r.*alpha2).*Ci).*legendreP(i-1,cos(t))-(Di.*r2.^(-i-1)+r2.^(-3./2).*besselk(i-1./2,r2.*alpha1).*Ei+r2.^(-3./2).*besselk(i-1./2,r2.*alpha2).*Fi).*legendreP(i-1,zet);
end
hold on
[DH1,h1]=contour(x,y,qr1,3,'-k');
%axis square;
title('$(a)$ $\ell=0.1,\;\alpha=1.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
%%%%%%%%%%%%%%%% $\frac{\textstyle a_1+a_2}{\textstyle h}=6.0,\;
hold on
t3 = linspace(0,2*pi,1000);
h2=0;
k2=0;
rr2=1;
x2 = rr2*cos(t3)+h2;
y2 = rr2*sin(t3)+k2;
set(plot(x2,y2,'-k'),'LineWidth',1.1);
fill(x2,y2,'w')
%axis square;
hold on
t2 = linspace(0,2*pi,1000);
h=dd;
k=0;
rr=2;
x1 = rr*cos(t2)+h;
y1 = rr*sin(t2)+k;
set(plot(x1,y1,'-k'),'LineWidth',1.1);
fill(x1,y1,'w')
%axis square;
axis off
1 comentario
Adam Danz
el 20 de Nov. de 2021
Shreen El-Sapa's answer moved here
I can not get the streamlines
Respuesta aceptada
Cris LaPierre
el 20 de Nov. de 2021
1 voto
qr1 is all NaNs. Assuming the countours are supposed to be your streamlines, you should check your equation. I'm not sure your for loop is doing what you intended. At the least, there is an issue with your calculation.
5 comentarios
Shreen El-Sapa
el 20 de Nov. de 2021
Editada: Cris LaPierre
el 20 de Nov. de 2021
edited code to make it more readable
A=[-4.7107 0.0012 -0.0056 0.0132 -0.0253 0.0435 -0.0689 0.1031 -0.1473 0.2040 -0.2737 0.3607 -0.4647 0.5927 -0.7425 0.9265 -1.1387 1.4014 -1.7014 2.0810 -2.5114 3.0805 -3.7224 4.6475 -5.6872 7.5039 -9.5388 16.4146 -25.4535 14.3236];
B=[-3.3794 0.0005 -0.0009 0.0006 -0.0003 0.0001 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0];
C=[6.8417 -0.0007 0.0007 -0.0003 0.0001 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0];
AA=[-4.7100 -0.0012 0.0058 -0.0132 0.0253 -0.0435 0.0689 -0.1032 0.1473 -0.2040 0.2737 -0.3608 0.4648 -0.5928 0.7426 -0.9266 1.1388 -1.4016 1.7016 -2.0813 2.5118 -3.0810 3.7230 -4.6482 5.6881 -7.5050 9.5403 -16.4171 25.4574 -14.3258];
BB=[-3.3789 -0.0005 0.0009 -0.0006 0.0003 -0.0001 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0];
CC=[6.8407 0.0007 -0.0008 0.0003 -0.0001 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0];
a = 1 ; %RADIUS
L=.13;
akm=1;gamma=0.3;arh=0.1;
alphaa=sqrt(((2+akm).*(akm./gamma)).^2+arh.^2);
betaa=(2.*akm.*arh.^2./gamma).^(0.25);
alpha1=sqrt((alphaa.^2+sqrt(alphaa.^4-4.*betaa.^4))./2);
alpha2=sqrt((alphaa.^2-sqrt(alphaa.^4-4.*betaa.^4))./2);
dd=5;
c =-a/L;
b =a/L;
m =a*50; % NUMBER OF INTERVALS
[x,y]=meshgrid([c+dd:(b-c)/m:b],[c:(b-c)/m:b]');
[I J]=find(sqrt(x.^2+y.^2)<(a-.1));
if ~isempty(I);
x(I,J) = 0; y(I,J) = 0;
end
r=sqrt(x.^2+y.^2);
t=atan2(y,x);
r2=sqrt(r.^2+dd.^2-2.*r.*dd.*cos(t));
zet=(r.^2-r2.^2-dd.^2)./(2.*r2.*dd);
warning on
psi1=0;
for i=2:3;
Ai=A(i-1);
Bi=B(i-1);
Ci=C(i-1);
AAi=AA(i-1);
BBi=BB(i-1);
CCi=C(i-1);
psi1=-psi1-(Ai.*r.^(-i-1)+r.^(-3./2).*besselk(i-1./2,r.*alpha1).*Bi+r.^(-3./2).*besselk(i-1./2,r.*alpha2).*Ci).*legendreP(i-1,cos(t))-(AAi.*r2.^(-i-1)+r2.^(-3./2).*besselk(i-1./2,r2.*alpha1).*BBi+r2.^(1./2).*besselk(i-1./2,r2.*alpha2).*CCi).*legendreP(i-1,zet);
end
[DH1,h1]=contour(x,y,psi1,20,'-k');
title('$(a)$ $\ell=0.1,\;\alpha=1.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
hold on
t3 = linspace(0,2*pi,1000);
h2=0;
k2=0;
rr2=1;
x2 = rr2*cos(t3)+h2;
y2 = rr2*sin(t3)+k2;
set(plot(x2,y2,'-k'),'LineWidth',1.1);
fill(x2,y2,'w')
t2 = linspace(0,2*pi,1000);
h=dd;
k=0;
rr=2;
x1 = rr*cos(t2)+h;
y1 = rr*sin(t2)+k;
set(plot(x1,y1,'-k'),'LineWidth',1.1);
fill(x1,y1,'w')
axis off
hold off
Cris LaPierre
el 20 de Nov. de 2021
Ok. Is this what you wanted? If not, you're going to have to describe better what it is you expect.
Shreen El-Sapa
el 20 de Nov. de 2021
Cris LaPierre
el 20 de Nov. de 2021
Personally, I use the streamlines function to create streamlines, not contour. However, even with streamlines, you will need to calculate and input the vector field components u and v.
Shreen El-Sapa
el 20 de Nov. de 2021
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