# I am given an array

1 view (last 30 days)
Diego Rosendo Pérez on 30 Nov 2021
Edited: Stephen23 on 6 Dec 2021
Thank you very much in advance.
a = [3 4 5 3 64 7 6 34 8 5 4 3];
##### 1 CommentShowHide None
Stephen23 on 6 Dec 2021
Edited: Stephen23 on 6 Dec 2021
Original question by Diego Rosendo Pérez retrieved from Google Cache:
I am given an array with different numbers and I have to compute the same array but with some values changed.
Hi, as you can see I am gven an initial array "a" and I have to create the code to return the same array but with some values changed according to some requirements I have to meet. Now, I have the values and their index but just do not know how to finish the exercise; I think that I need to use a for loop but I just do not know how to code the last line so that I obtain the same array "a" but with some values changed. Thank you very much in advance.
a = [3 4 5 3 64 7 6 34 8 5 4 3];
m = mean(a);
st = std(a);
an = abs(a - m) > st;
ind = find(an);

Yongjian Feng on 30 Nov 2021
Do you mean:
a = [3 4 5 3 64 7 6 34 8 5 4 3];
m = mean(a);
st = std(a);
an = abs(a - m) > st;
ind = find(an);
a(ind) = an(ind)
##### 1 CommentShowHide None
Yongjian Feng on 30 Nov 2021
Edited: Yongjian Feng on 30 Nov 2021
This one?
a = [3 4 5 3 64 7 6 34 8 5 4 3];
m = mean(a);
st = std(a);
an = abs(a - m) > st;
ind = find(an);
a(ind) = 4 % replace all the meet the requirements with 4

### Categories

Find more on Matrix Indexing in Help Center and File Exchange

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by