why do I suddenly get a gain value in my transfer function?

this is my transfer function:
x=s/[(2*s^2)+(3*s)+1]
when I tried to obtained the zeros and poles value by using zpk function suddenly I got a gain value.
any advice will be much appreciated. thank you in advance

 Respuesta aceptada

Jon
Jon el 1 de Dic. de 2021
Your original expression and the one found by zpk are the same. zpk just factored out the 2 from denominator.

2 comentarios

Note that 1/(2s^2 + 3s + 1) = 1/(2*(s^2 + 1.5s + 0.5), which equals, 0.5/(s^2 + 1.5s + 0.5). So you also have a gain of 0.5 in your original expession
Thanks. My mistake I didn't noticed that

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre MATLAB en Centro de ayuda y File Exchange.

Productos

Versión

R2021b

Preguntada:

el 1 de Dic. de 2021

Comentada:

el 1 de Dic. de 2021

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by