sort a matrix depending on first row

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Raviteja
Raviteja el 17 de Sept. de 2011
Comentada: Bruno Luong el 3 de Ag. de 2020
I have a matrix B
>> B
B =
5.0000 1.0000 6.0000 3.0000
0.6076 0.4943 0.1097 0.4754
-0.1178 -1.4831 1.1287 1.1741
0.6992 -1.0203 -0.2900 0.1269
0.2696 -0.4470 1.2616 -0.6568
depending on the first rwo values I want to sort the data. i.e., my result should look like this
>>
ans=
1.0000 3.0000 5.0000 6.0000
0.4943 0.4754 0.6076 0.1097
-1.4831 1.1741 -0.1178 1.1287
-1.0203 0.1269 0.6992 -0.2900
-0.4470 -0.6568 0.2696 1.2616
How to do this?

Respuestas (2)

Andrei Bobrov
Andrei Bobrov el 17 de Sept. de 2011
Editada: Stephen23 el 11 de Abr. de 2019
out = sortrows(B.',1).'
variant
[~,inx]=sort(B(1,:));
out = B(:,inx);
  3 comentarios
Barrett Durtschi
Barrett Durtschi el 3 de Ag. de 2020
Thank you for this answer! What would I change in the statement if I wanted the first four row values?
Bruno Luong
Bruno Luong el 3 de Ag. de 2020
out = sortrows(B(1:4,:).',1).'

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TAB
TAB el 17 de Sept. de 2011
[mat inx]=sort(b(1,:));
SortedMat=[b(:,inx(1)),b(:,inx(2)),b(:,inx(3)),b(:,inx(4))];

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