# vectorization my user defined function

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Adarsh Tiwari on 5 Dec 2021
Commented: Adarsh Tiwari on 6 Dec 2021
I have the following array manipulations. How can i convert for loop'for loop' in a Vectorized expression\function.
time =[
5 10
3 5
5 3
5 7
3 5];
cost =[
6 3
4 3
7 10
10 5
14 9];
x=[1 1 1 1 1;2 2 2 2 2;1 2 1 2 1];
Np=size(x,1)
for i=1:Np
fun(i,1:2) = [max([time(1,x(i,1))+time(3,x(i,3))+time(5,x(i,5)),...
time(1,x(i,1))+time(4,x(i,4)),time(2,x(i,2))+...
time(5,x(i,5))]),cost(1,x(i,1))+cost(2,x(i,2))+...
cost(3,x(i,3))+cost(4,x(i,4))+cost(5,x(i,5))];
end
##### 2 CommentsShowHide 1 older comment
Adarsh Tiwari on 6 Dec 2021
Thanks DGM
It is definitely more compact than mine but I needed vectorized form.

Abolfazl Chaman Motlagh on 5 Dec 2021
a simple quick solution is :
time =[5,10;3,5;5,3;5,7;3,5];
cost =[6,3;4,3;7,10;10,5;14,9];
x=[1 1 1 1 1;2 2 2 2 2;1 2 1 2 1];
fun = [max([time(1,x(:,1))'+time(3,x(:,3))'+time(5,x(:,5))',...
time(1,x(:,1))'+time(4,x(:,4))',time(2,x(:,2))'+...
time(5,x(:,5))'],[],2),cost(1,x(:,1))'+cost(2,x(:,2))'+...
cost(3,x(:,3))'+cost(4,x(:,4))'+cost(5,x(:,5))']
fun = 3×2
13 41 18 30 13 35
Adarsh Tiwari on 6 Dec 2021
It serves my purpose. i may now go ahead with my code.