Finding points of intersection between Curve and sides of a square
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
clc
clear all
close all
S = 2;
a = 0.1
b = 0.2
p_crd = [0,S]
p_x = [((1+S)/2)+a S+0.5 S+0.5 ((1+S)/2) ((1+S)/2)];
p_y = [(1+S)/2 (1+S)/2 S+0.5 S+0.5 ((S+1)/2)+b];
plate = plot(p_x,p_y);
n =15;
axis([0,3,0,3]);
hold on
theta = linspace(0,pi/2,1000);
h = 1.5;
k = 1.5;
del = linspace(0,((S)/sqrt(2))-0.25,n)
for i = 1:n
hold on
a2 = a+del(i);
b2 = b+del(i);
x{i} = h + a2*cos(theta);
y{i} = k + b2*sin(theta);
plot(x{i},y{i});
end
axis square
As you can see, I want the ellipses to be restricted within the sides of square and know their intersecting points. I tried the inpolygon function but it resulted in lines within the square but not upto the side of the square plate. If someone can please help, it would be highly appreciated.
0 comentarios
Respuestas (1)
Matt J
el 11 de Dic. de 2021
If you make the appropriate change of coordinates, your ellipses will become circles and your square will become a more general polygon. You can then use the methods discussed in this similar thread.
0 comentarios
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!