how to find the distance?

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bsd
bsd el 18 de Sept. de 2011
Hai,
I have drawn a line between two points, I need to find the length(distance) of that line between those two points. Is there a command in matlab that could find the length(distance) of the line? Looking forward to hearing from you soon.
BSD

Respuestas (2)

Jan
Jan el 18 de Sept. de 2011
point1 = rand(1, 3);
point2 = rand(1, 3);
distance = norm(point1 - point2);
Or:
d = point1 - point2;
distance = sqrt(d * d');
Or with the fast C-Mex FEX: DNorm2, which operates on rows or columns of matrices also:
distance = DNorm2(point1 - point2);
  2 comentarios
Michael Leung
Michael Leung el 19 de Sept. de 2011
bsd, I'm not sure in how many dimensions you are working in, but in 2D, and 3D, norm would be the function you are looking for.
It uses simple Pythagorean theorem to find the distance.
(I'm not sure if Pythagorean would apply in higher dimensions, I can not visualize how it would work! XD)
Jan
Jan el 19 de Sept. de 2011
The 2-norm (Euclidean norm) works in arbitrary dimensions. It is: SQRT(SUM(x.^2)). In my example SUM(x.^2) is implemented faster using the DOT product x*x', which is calculated by the fast BLAS library.

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Walter Roberson
Walter Roberson el 18 de Sept. de 2011
Use hypot
distance = hypot(point1 - point2);
This assumes, of course, that the line is a straight one and the measurement is in Euclidean geometry, and the distance metric is the Euclidean distance.
  2 comentarios
Jan
Jan el 18 de Sept. de 2011
@Walter: The documentation you've linked to explains, that HYPOT needs two inputs. HYPOT(point1, point2) does also not measure the distance.
Walter Roberson
Walter Roberson el 19 de Sept. de 2011
Yes, you are right. But if you are working in 2d, then splitting the difference in two a and b components and using hypot() will generate more precise answers if the differences might be quite small, especially below sqrt(eps(0)) (approximately 1E-162)

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