How to modify scatter3 default 'mouseover' display

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Roger Breton
Roger Breton el 16 de Dic. de 2021
Editada: Adam Danz el 28 de Dic. de 2021
Is it possible to change the way the values are displayed in scatter3 when I mouse over a given data points?
I have created this plot, representating a number of CIE Lab data points (see below). The problem is that, ideally, the Labels ought to read Lab (and not XYZ) and the order needs to change from bottom to top. Such that, in the screen capture, I would like to have scatter3 show
L 87.8179
a -79.2574
b 80.987
  2 comentarios
Adam Danz
Adam Danz el 16 de Dic. de 2021
According to the values in the datatip and the axis labels, the datatip should be
b 87.8179 % not L
a -79.2574
L 80.987 % not b
Roger Breton
Roger Breton el 16 de Dic. de 2021
You are right (and I was wrong) :
L = 80.987
a = -79.2574
b = 87.8179
In other words, X = L and Z = b

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Respuestas (1)

Adam Danz
Adam Danz el 16 de Dic. de 2021
Editada: Adam Danz el 16 de Dic. de 2021
Note that this demo assigns axis labels according your desciption of the desired datatip labels (L,a,b) whereas in your image, the axes appear to be x=b, y=a, z=L, unless the camera view angle or the camera up vector has been changed from default.
% Create scatter, return handle
h = scatter3(rand(1,10),rand(1,10),rand(1,10));
xlabel('L')
ylabel('a')
zlabel('b')
% Redefine labels
h.DataTipTemplate.DataTipRows(1).Label = 'L';
h.DataTipTemplate.DataTipRows(2).Label = 'a';
h.DataTipTemplate.DataTipRows(3).Label = 'b';
% Show datatip
datatip(h, h.XData(1),h.YData(1),h.ZData(1));
Alternatively to avoid mislableing the x|y|z values, you could just use the xlabel, ylabel, zlabel strings,
ax = ancestor(h, 'axes'); % get axis handle
h.DataTipTemplate.DataTipRows(1).Label = ax.XLabel.String;
h.DataTipTemplate.DataTipRows(2).Label = ax.YLabel.String;
h.DataTipTemplate.DataTipRows(3).Label = ax.ZLabel.String;
  8 comentarios
Adam Danz
Adam Danz el 17 de Dic. de 2021
It's very simple, the data tip labels are in order of X Y Z, or in your plot, b a L.
This is what I've been trying to tell you in almost all of my comments above.

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