Multidimensional Array deleting entire max record keeping information across in order
2 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
I have the following loop:
sz = 20;
m = zeros(size(sz));
for i = 1:sz
[max_val, position] = max(sh(:)); %Find Max Position
m(i,:) = [position]; %Store Max Position in "m"
sh(sh==max(sh)) = []; %Delete current max value of "sh"
end
What I am trying to do here is pretty much to extract to "m" the top 20 highest values in "sh" (sh is a 3D matrix - 100x60x95). What i am not sure is happening is if " sh(sh==max(sh)) = []; " deletes only the value or the entire "row" containig the data of the max value.
What i ultimately need is once i delete the value, i need to delete everything else pertaining to that value in the matrix so when values shift they keep their order. Thanks so much for the help!
3 comentarios
Respuesta aceptada
Voss
el 23 de Dic. de 2021
If all you need is the 20 maximum values and their positions (either linear index or subscript index), then you can do this:
sh_temp = sh;
sh_temp(isnan(sh_temp)) = -Inf;
[sh_sort,ii] = sort(sh_temp(:),'descend');
sz = 20;
max_vals = sh_sort(1:sz);
m = ii(1:sz); % linear index of max_vals
[r,c,p] = ind2sub(size(sh),m); % row, column, 'page' index for each of max_vals
12 comentarios
Más respuestas (0)
Ver también
Categorías
Más información sobre Matrix Indexing en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!