# pie chart subdivision of a sector

3 views (last 30 days)
Maria Ali on 26 Dec 2021
Commented: Maria Ali on 26 Dec 2021 i have to create a pi chart as shown in the picture from the given data. how can i subdivide a sector as is shown in the picture

Chunru on 26 Dec 2021
x = [73.1 39.3 29.9 8.2 7.2 6.2];
xp = x/sum(x);
x1 = [xp(1:2) sum(xp(3:end))];
x2 = xp(3:end);
figure; hold on
theta0 = 0;
colors = ['r','g','b','c','m','y', 'w'];
for i=1:length(x1)
theta1 = theta0 + x1(i)*360;
theta = linspace(theta0, theta1, 50)';
%[0.5*cosd(theta); 1*cosd(flip(theta))], [0.5*sind(theta); 1*sind(flip(theta))]
patch([0.5*cosd(theta); 1*cosd(flip(theta))], [0.5*sind(theta); 1*sind(flip(theta))], colors(i));
text(0.75*cosd(mean(theta)), 0.75*sind(mean(theta)), num2str(i))
theta0 = theta1;
end
theta0 = sum(x1(1:end-1))*360;
for i=1:length(x2)
theta1 = theta0 + x2(i)*360;
theta = linspace(theta0, theta1, 50)';
%[0.5*cosd(theta); 1*cosd(flip(theta))], [0.5*sind(theta); 1*sind(flip(theta))]
patch([1*cosd(theta); 1.5*cosd(flip(theta))], [1*sind(theta); 1.5*sind(flip(theta))], colors(3));
text(1.25*cosd(mean(theta)), 1.25*sind(mean(theta)), char('A'+(i-1)))
theta0 = theta1;
end
axis equal
axis off Maria Ali on 26 Dec 2021
Thank you so much for your help.

R2021b

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