Finding Rise Time from System Response

1 visualización (últimos 30 días)
Philip Asante-Mireku
Philip Asante-Mireku el 29 de Dic. de 2021
Editada: Philip Asante-Mireku el 29 de Dic. de 2021
I am trying to find appropriate sample time from the open loop response from my system for use in model predictive control:
A=[-1 1.6 0;0 0 1;0 0 -11.76];
B=[0; 0; 1];
C=[50 0 0];
D=zeros(1,1);
Cont_plant=ss(A,B,C,D); %continuous state space dynamics of plant
step(Cont_plant)
How do i get get the rise time,settling time since this system is not open loop stable? I tried to put it in feedback and still this:
A=[-1 1.6 0;0 0 1;0 0 -11.76];
B=[0; 0; 1];
C=[50 0 0];
D=zeros(1,1);
Cont_plant=ss(A,B,C,D); %continuous state space dynamics of plant
step(Cont_plant)
G=feedback(Cont_plant,1)
G = A = x1 x2 x3 x1 -1 1.6 0 x2 0 0 1 x3 -50 0 -11.76 B = u1 x1 0 x2 0 x3 1 C = x1 x2 x3 y1 50 0 0 D = u1 y1 0 Continuous-time state-space model.
step(G)

Respuestas (1)

Burhan Burak AKMAN
Burhan Burak AKMAN el 29 de Dic. de 2021
You can use 'stepinfo' function like below.
A=[-1 1.6 0;0 0 1;0 0 -11.76];
B=[0; 0; 1];
C=[50 0 0];
D=zeros(1,1);
Cont_plant=ss(A,B,C,D); %continuous state space dynamics of plant
step(Cont_plant)
G=feedback(Cont_plant,1);
step(G)
stepinfo(G)
ans = struct with fields:
RiseTime: 0.4450 TransientTime: 17.6458 SettlingTime: 17.6458 SettlingMin: 0.4255 SettlingMax: 1.7478 Overshoot: 74.7832 Undershoot: 0 Peak: 1.7478 PeakTime: 1.3568
  1 comentario
Philip Asante-Mireku
Philip Asante-Mireku el 29 de Dic. de 2021
Editada: Philip Asante-Mireku el 29 de Dic. de 2021
Is the closed loop response rise time appropriate for use in Model Predictive control for finding prediction horizon and control horizon?

Iniciar sesión para comentar.

Categorías

Más información sobre Programming en Help Center y File Exchange.

Productos


Versión

R2021a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by