Non-typical system of nonlinear equations

1 visualización (últimos 30 días)
KarolN
KarolN el 30 de Dic. de 2021
Comentada: KarolN el 30 de Dic. de 2021
I tried to solve this system of equations, using fsolve and various newton-raphson functions, but to no avail:
x*y-z^2-1 = 0
x*y*z+y^2-x^2-2 = 0
e^x+z-e^y-3 = 0
How to bite this?

Respuesta aceptada

Walter Roberson
Walter Roberson el 30 de Dic. de 2021
Editada: Walter Roberson el 30 de Dic. de 2021
There two real-valued solutions and two complex-valued solutions.
syms x y z
eq1=x.*y-z.^2-1 == 0;
eq2=x.*y.*z+y.^2-x.^2-2 == 0;
eq3=exp(x)+z-exp(y)-3 == 0;
eqns = [eq1, eq2, eq3];
string(eqns)
ans = 1×3 string array
"x*y - z^2 - 1 == 0" "y^2 - x^2 + x*y*z - 2 == 0" "z + exp(x) - exp(y) - 3 == 0"
solx = solve(eqns(1),x)
solx = 
eqns2 = subs(eqns(2:end), x, solx)
eqns2 = 
soly = solve(eqns2(1), y, 'maxdegree', 4)
soly = 
eqns3 = subs(eqns2(2:end), y, soly)
eqns3 = 
solz = arrayfun(@vpasolve, eqns3)
solz = 
backz = solz
backz = 
backy = simplify(arrayfun(@(Y,Z) subs(Y, z, Z), soly, backz))
backy = 
backx = simplify(arrayfun(@(Y,Z) subs(solx, {y, z}, {Y, Z}), backy, backz))
backx = 
X = double(backx(:));
Y = double(backy(:));
Z = double(backz(:));
sols = table(X, Y, Z)
sols = 4×3 table
X Y Z _____________________________________ ___________________________________ ___________________________________ 1.77767191801074+0i 1.42396059788849+0i 1.2374711177317+0i 0.312665572783089-1.92640000714264i -3.6173710991782+6.60644699784i 3.50141439437029+1.29006613162679i -6.00007674738141+0i -1.82891828362435+0i 3.15810862169672+0i -0.0235291143948645-1.64861787491676i 0.226753337733853+4.16490693352808i 2.42290841496534-0.097367728502186i
  1 comentario
KarolN
KarolN el 30 de Dic. de 2021
The best answer of all submitted and works perfect! Thanks! Happy New Year!

Iniciar sesión para comentar.

Más respuestas (1)

Yusuf Suer Erdem
Yusuf Suer Erdem el 30 de Dic. de 2021
Editada: Walter Roberson el 30 de Dic. de 2021
Try these codes below please;
syms x y z
eq1=x.*y-z.^2-1 == 0;
eq2=x.*y.*z+y.^2-x.^2-2 == 0;
eq3=exp(x)+z-exp(y)-3 == 0;
solve(eq1,eq2,eq3,x,y,z)
Warning: Unable to solve symbolically. Returning a numeric solution using vpasolve.
ans = struct with fields:
x: 1.7776719180107405499159549245637 y: 1.4239605978884890880290410180788 z: 1.2374711177317033717819050711785

Productos


Versión

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by