How to split 36x1 cell array into 36x3 cell array?
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I have the attached text file which I need to split into 3 columns.
First column will be 36x1 with elements # {which I do not need}
Second column should contain the sentences up to :
Third column will contain the data { Kinetic Energy, Counts per Second .......}
I am using the following code, but I end up with 36x1 cell and I could not seperate the columns.
Thank you very much in advance for your help!!
clear all
close all
FileName=sprintf('file.txt');
fid= fopen(FileName, 'rt');
tline = fgetl(fid);
header = cell(0,1);
while ischar(tline)
header{end+1,1} = tline
tline = fgetl(fid);
if strcmp(tline,' Workfunction: ')== 1
sprintf('end')
break
end
end
header = split(header(:,1),' ');
fclose(fid);
Respuesta aceptada
Más respuestas (1)
fid = fopen('file.txt');
data = fread(fid);
fclose(fid);
c_data = strsplit(char(data).',newline());
out = repmat({''},numel(c_data),3);
for i = 1:numel(c_data)
if isempty(c_data{i}) || c_data{i}(1) ~= '#'
continue
end
out{i,1} = '#';
idx = find(c_data{i} == ':',1);
if isempty(idx)
continue
end
out{i,2} = strtrim(c_data{i}(2:idx));
out{i,3} = strtrim(c_data{i}(idx+1:end));
end
disp(out);
1 comentario
Mohammed Qahosh
el 3 de En. de 2022
And sorry for late reply, I had to wait to try it on my office 2021 Matlab. As I am still using 2017 on my personal laptop and with this version still I get en error.
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