Fortran to matlab code

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Matlabuser
Matlabuser el 12 de Nov. de 2014
Comentada: Matlabuser el 17 de Nov. de 2014
Hi everyone, I have a code in fortran and I want to convert that code in matlab. But problem is that, in fortran I have I=-N+1:N+1;
But in matlab, If I take the negative no. I have the problem of indexing. Can anyone please tell me, how I can solve this problem?
Thanks

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Torsten
Torsten el 12 de Nov. de 2014
If you mean
I=-(N+1):(N+1)
then shift the indices by N+2 for the MATLAB application.
Then in_Matlab I will be I=1:(2*N+3)
Best wishes
Torsten.
  2 comentarios
Matlabuser
Matlabuser el 12 de Nov. de 2014
Thank you Torsten !!!
Matlabuser
Matlabuser el 17 de Nov. de 2014
a=-N+2
i=-N+1,N-1
p(i)=p(a)-p(a-2)
a=a+1
I did not know how to change this in matlab

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