why doesnt it work
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
function x = ss_dtmf(number,dt,nd,np)
nl = length(number);
x = [];
t = 0:1:nd;
t = t*dt;
tp = 0:1:np;
xp = zeros(1,length(tp));
for i=1:nl
xi = ss_dtmf1(number(i),t);
x = [x,xi];
x = [x,xp];
end
end
5 comentarios
Walter Roberson
el 18 de En. de 2022
The line
Function for DTMF:
is not a valid executable line. You need to comment it out.
Cris LaPierre
el 18 de En. de 2022
Try commenting out your comments so that you can run your code.
Functions must be called, so I'm asking how you are calling your function ss_dtmf? Specifically what are your input values for number, dt, nd, and np?
What error messages are you getting? Please copy and share all the red text.
Respuestas (1)
David Hill
el 18 de En. de 2022
function x = ss_dtmf(number,dt,nd,np)
x=[];
for i=1:length(number)
x = [x,ss_dtmf1(number(i),0:nd:dt),ss_dtmf1(12,0:np:dt)];
end
end
function x = ss_dtmf1(n,t)
f=[941,697,697,697,770,770,770,852,852,852,941,941,0;1336,1209,1336,1477,1209,1336,1477,1209,1336,1477,1209,1477,0];
x=sin(2*pi*f(1,n+1)*t)+sin(2*pi*f(2,n+1)*t);
end
4 comentarios
David Hill
el 19 de En. de 2022
This should do exactly what you want.
function x = ss_dtmf(number,dt,nd,np)
x=[];
lt=linspace(0,dt,nd);
lp=linspace(0,dt,np);
for i=1:length(number)
x = [x,ss_dtmf1(number(i),lt),ss_dtmf1(12,lp)];
end
plot(x);
end
function x = ss_dtmf1(n,t)
f=[941,697,697,697,770,770,770,852,852,852,941,941,0;1336,1209,1336,1477,1209,1336,...
1477,1209,1336,1477,1209,1477,0];
x=sin(2*pi*f(1,n+1)*t)+sin(2*pi*f(2,n+1)*t);
end
for example:
x=ss_dtmf([2 0 8 7 3 9 6 1 0 3],.1,1000,50);
Ver también
Categorías
Más información sobre MATLAB Mobile en Help Center y File Exchange.
Productos
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!