plot of equation of function

k0=2*pi/632.8e-9;
n1=1.512;
n2=1.521;
n3=2.66;
n4=0.15+1i*3.5;
t2=2e-6;
m=0;
t3=1e-9:1e-6;
k1=@(x)  k0*sqrt(n1^2-x^2);
k2=@(x)   k0*sqrt(n2^2-x^2);
k3=@(x)   k0*sqrt(n3^2-x^2);
k4=@(x)  k0*sqrt(n4^2-x^2);


y=@(x,t3)-(k2)*t2+atan(k1/1i*k2)+atan((k3/k2)*tan(atan(k4/1i*k2)-k3*t3))+m*pi;
plot(t3,real(x))
plot(t3,imag(x)

[KSSV]

@shiv gaur You are continuously asking the same kind of questions, without completing/ commenting/ closing/ acknowledging the previous questions. Please don't do that. If the questions are same, discuss at the same question.

In the above code, t2 is not defined. x is not defined. What exactly you are trying to achieve? Ask a question so that people can understand to help you.

The above question, is simple. You have used anonymous function. Substitute x in k1, k2, k3, k4 and then use those values in the formula y with t's defined. Then use plot.

[shiv gaur]

this is function of x and t3 first we have to find root of equation then plot

[shiv gaur]

if question is simple pl solve the problem

[KSSV]

If question is simple, that doesn't mean that we will do your work. You have to give some attempt and if you stuck you are welcome to ask a question.

[shiv gaur]

it is not so simple question

[KSSV]

If you want to find the root...use syms. Read about solve and syms.

[shiv gaur]

this is the program pl plot t3=1e-9 to 1e-6 vs real x

program is running

[b]=fminsearch(@(b) abs(trial0(complex(b(1),b(2)))) ,[1,1]);

beta=complex(b(1),b(2))

function beta1 = trial0(beta)

n1=1.512;

n2=1.521;

n3=4.1-1i*0.211;

n4=1;

lambda = 633e-9;

k0 = (2*pi)/lambda;

t2 = 2e-6;

%t3=0;

m=0;

S1 = k0*sqrt(n1^2-beta^2);

S2 = k0*sqrt(n2^2-beta^2);

S3 = k0*sqrt(n3^2-beta^2);

S4 = k0*sqrt(n4^2-beta^2);

beta1=-(S2)*t2+atan(S1/1i*S2)+atan((S3/S2).*tan(atan(S4/1i*S2)-S3*t3))+m*pi;

end

how to plot pl help to write where we store the value of t3 plot

[shiv gaur]

i try but empty value showing