Array indices must be positive integers or logical values

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Munirah Zaid
Munirah Zaid el 25 de En. de 2022
Comentada: Munirah Zaid el 25 de En. de 2022
Hello, help me to solve this. I'm not into Matlab but doing this just for my assignment purpose. Had googled it but don't understand.
i=0:0.1:1;
for i = i
xt(i) = @(t) (-0.05)*t(i)^5+0.25*t(i)^4+t(i)+2-exp(-t(i));
yt(i) = @(t) t(i)^3+1;
zt(i) = @(t) (0.25*t(i)^4)+t(i)-exp(-t(i));
end
Array indices must be positive integers or logical values.
  1 comentario
Ankit
Ankit el 25 de En. de 2022
Editada: Ankit el 25 de En. de 2022
It is clear from the error that your index should be positive integer ("Integers that are greater than zero are positive integers" i.e. 1,2,3...etc)

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Respuesta aceptada

KSSV
KSSV el 25 de En. de 2022
t=0:0.1:1;
nt = length(t) ;
xt = zeros(nt,1) ;
for i = 1:length(t)
xt(i) = (-0.05)*t(i)^5+0.25*t(i)^4+t(i)+2-exp(-t(i));
yt(i) = t(i)^3+1;
zt(i) = (0.25*t(i)^4)+t(i)-exp(-t(i));
end
Actually you can do the same without loop.
i=0:0.1:1;
xt = (-0.05)*t.^5+0.25*t.^4+t+2-exp(-t);
yt = t.^3+1;
zt = (0.25*t.^4)+t-exp(-t);

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