converting only certain cells to a matrix

consider the following example
a = { rand(1877958,7); rand(1251972,7); rand(4564357,7) };
i want only the first two cells to be converted to a matrix. i know that the rows are not the same but the remaining rows can be filled with zeros. how can i do that in such a way so that the output has 14 columns meaning the matrices are put adjacent to each other. thanks

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Azzi Abdelmalek
Azzi Abdelmalek el 29 de Nov. de 2014
Editada: Azzi Abdelmalek el 29 de Nov. de 2014
a = { rand(1877958,7); rand(1251972,7); rand(4564357,7) };
n=max(cellfun(@(x) size(x,1) , a(1:2)) )
b=cell2mat(cellfun(@(x) [x;zeros(n-size(x,1),7)],a(1:2)','un',0));

6 comentarios

AA
AA el 29 de Nov. de 2014
Is there a way to do this conversion without the zeros?
Azzi Abdelmalek
Azzi Abdelmalek el 29 de Nov. de 2014
How? you must get the same number of rows if you want to concatenate them horizontally
AA
AA el 29 de Nov. de 2014
You are right. Your formula concentrates them vertically. How can i concentrate the tables horizontally so that i get 14 columns. Thanks
Azzi Abdelmalek
Azzi Abdelmalek el 29 de Nov. de 2014
No, they are horizontally concatenated, look at the size, it's 1877958x14
AA
AA el 29 de Nov. de 2014
I apologize. You r right. How would I vertically arrange the tables without zeros and 7 columns. Thanks
This is easier
b=cell2mat(a(1:2));

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AA
el 29 de Nov. de 2014

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el 29 de Nov. de 2014

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