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How to differentiate vectors

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Ikechi Ndamati
Ikechi Ndamati el 15 de Feb. de 2022
Comentada: Star Strider el 17 de Feb. de 2022
Hello, please I have a code with lambda and n given below. Please how do I obtain d(n)/d(lambda) and d^2(n)/d(lambda)^2 i.e. the first and second deriviative of n wrt lambda?
lambda = linspace(0.5,2.5);
n = [1.55155531233953 1.54949576778463 1.54767969992980 1.54606941077293 1.54463432037936 1.54334939304258 1.54219395936135 1.54115082328366 1.54020557725122 1.53934607132757 1.53856199764777 1.53784456219577 1.53718622338909 1.53658048225698 1.53602171281363 1.53550502400216 1.53502614662547 1.53458134019413 1.53416731575664 1.53378117163556 1.53342033964695 1.53308253988297 1.53276574252631 1.53246813546774 1.53218809673566 1.53192417093373 1.53167504903131 1.53143955097005 1.53121661064518 1.53100526289637 1.53080463220578 1.53061392285076 1.53043241030050 1.53025943367952 1.53009438914900 1.52993672407995 1.52978593191141 1.52964154760293 1.52950314360382 1.52937032627300 1.52924273269261 1.52912002782641 1.52900190198108 1.52888806853379 1.52877826189461 1.52867223567629 1.52856976104774 1.52847062525013 1.52837463025771 1.52828159156731 1.52819133710247 1.52810370622009 1.52801854880867 1.52793572446860 1.52785510176605 1.52777655755305 1.52769997634709 1.52762524976427 1.52755227600092 1.52748095935889 1.52741120981038 1.52734294259859 1.52727607787089 1.52721054034140 1.52714625898047 1.52708316672849 1.52702120023196 1.52696029959983 1.52690040817834 1.52684147234282 1.52678344130489 1.52672626693392 1.52666990359143 1.52661430797744 1.52655943898778 1.52650525758144 1.52645172665720 1.52639881093877 1.52634647686784 1.52629469250434 1.52624342743341 1.52619265267854 1.52614234062043 1.52609246492120 1.52604300045342 1.52599392323372 1.52594521036064 1.52589683995631 1.52584879111185 1.52580104383610 1.52575357900747 1.52570637832878 1.52565942428470 1.52561270010188 1.52556618971130 1.52551987771288 1.52547374934221 1.52542779043906 1.52538198741785 1.52533632723963];
plot(n,lambda)
ylabel('n','FontWeight','bold','FontSize',14)
xlabel('lambda','FontWeight','bold','FontSize',14)

Respuesta aceptada

Star Strider
Star Strider el 15 de Feb. de 2022
Use the gradient function —
lambda = linspace(0.5,2.5);
n = [1.55155531233953 1.54949576778463 1.54767969992980 1.54606941077293 1.54463432037936 1.54334939304258 1.54219395936135 1.54115082328366 1.54020557725122 1.53934607132757 1.53856199764777 1.53784456219577 1.53718622338909 1.53658048225698 1.53602171281363 1.53550502400216 1.53502614662547 1.53458134019413 1.53416731575664 1.53378117163556 1.53342033964695 1.53308253988297 1.53276574252631 1.53246813546774 1.53218809673566 1.53192417093373 1.53167504903131 1.53143955097005 1.53121661064518 1.53100526289637 1.53080463220578 1.53061392285076 1.53043241030050 1.53025943367952 1.53009438914900 1.52993672407995 1.52978593191141 1.52964154760293 1.52950314360382 1.52937032627300 1.52924273269261 1.52912002782641 1.52900190198108 1.52888806853379 1.52877826189461 1.52867223567629 1.52856976104774 1.52847062525013 1.52837463025771 1.52828159156731 1.52819133710247 1.52810370622009 1.52801854880867 1.52793572446860 1.52785510176605 1.52777655755305 1.52769997634709 1.52762524976427 1.52755227600092 1.52748095935889 1.52741120981038 1.52734294259859 1.52727607787089 1.52721054034140 1.52714625898047 1.52708316672849 1.52702120023196 1.52696029959983 1.52690040817834 1.52684147234282 1.52678344130489 1.52672626693392 1.52666990359143 1.52661430797744 1.52655943898778 1.52650525758144 1.52645172665720 1.52639881093877 1.52634647686784 1.52629469250434 1.52624342743341 1.52619265267854 1.52614234062043 1.52609246492120 1.52604300045342 1.52599392323372 1.52594521036064 1.52589683995631 1.52584879111185 1.52580104383610 1.52575357900747 1.52570637832878 1.52565942428470 1.52561270010188 1.52556618971130 1.52551987771288 1.52547374934221 1.52542779043906 1.52538198741785 1.52533632723963];
plot(n,lambda)
ylabel('\lambda','FontWeight','bold','FontSize',14)
xlabel('n','FontWeight','bold','FontSize',14)
dndlambda = gradient(n) ./ gradient(lambda); % First Numerical Derivative
d2ndlambda2 = gradient(dndlambda) ./ gradient(lambda); % Second NMumerical Derivative
figure
yyaxis left
plot(lambda, n, 'DisplayName','Original Data')
yyaxis right
plot(lambda, dndlambda, 'DisplayName','First Derivative')
hold on
plot(lambda, d2ndlambda2, 'DisplayName','Second Derivative')
hold off
grid
xlabel('\lambda','FontWeight','bold','FontSize',14)
legend('Location','best')
Note that the first asrgument to plot is the independent variable and the second argument is the dependent variable. I corrected the axis labels in the firsst plot to reflect this.
I used yyaxis because the magnitudes between the original data and the derivatives are significantly different.
.
  2 comentarios
Ikechi Ndamati
Ikechi Ndamati el 17 de Feb. de 2022
Thanks so much @Star Strider
Star Strider
Star Strider el 17 de Feb. de 2022
As always, my pleasure!

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