how to calculate anomaly ?
11 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Hi all,
I want to extract data based on the months using this function 'monthofyear' to calculate anomalies.
The written code shows the wrong results.
Any help is appreciated
anom=[];
i=1;
for yy = 2019
ndays = eomday(yy, 1:12);
for mm = 1:12
for dd = 1:ndays(mm)
monthofy = month(datetime(yy,mm,dd),'monthofyear');
nn = norm(:,:,monthofy);
anom(:,:,i) = sez_chl - nn; %sez_chl is 3d matrix 72*46*46
i=i+1;
end
end
end
0 comentarios
Respuestas (1)
Image Analyst
el 15 de Feb. de 2022
There is a whole family of "outlier" functions, like rmoutliers(), etc. Look into them.
3 comentarios
Image Analyst
el 17 de Feb. de 2022
Note that you forgot to read this
and attach your data, so all we can do is guess. We have not seen your time series data, sez_chl, or norm.
Ver también
Categorías
Más información sobre Testing Frameworks en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!