How to solve Lagrange polynomial?

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Tariq Saleh
Tariq Saleh el 15 de Feb. de 2022
Respondida: Walter Roberson el 15 de Feb. de 2022
I'm trying to find the function of these data set , but the output is wrong
what's wrong with this code?
syms x
x0=1;
x1=2;
x2=3;
x3=4;
y0=3;
y1=5;
y2=7;
y3=9;
L(x0)=(x-x1)*(x-x2)*(x-x3)/(x0-x1)*(x0-x2)*(x0-x3);
L(x1)=(x-x0)*(x-x2)*(x-x3)/(x1-x0)*(x1-x2)*(x1-x3);
L(x2)=(x-x0)*(x-x1)*(x-x3)/(x2-x0)*(x2-x1)*(x2-x3);
L(x3)=(x-x0)*(x-x1)*(x-x2)/(x3-x0)*(x3-x1)*(x3-x2);
y=L(x0)*(y1)+L(x1)*(y2)+L(x3)*(y3);
simplify(y);
pretty(simplify(y))
3 2 - 10 x + 122 x - 448 x + 516

Respuestas (1)

Walter Roberson
Walter Roberson el 15 de Feb. de 2022
Those assignments to L(x0) and so on are not defining the meaning of L when given an input variable named x0, and a different meaning if the input is x1 and so on. Instead each of those is overwriting all of the symbolic function named L.
MATLAB does not permit you to define a symbolic function by cases. You cannot, for example, define
f(0) = 1
f(t) = t*f(t-1)
in order to define the factorial function. There are computer programming languages that permit that kind of definition by cases, but matlab is not one of them. You need to either define a single piecewise() function that covers the four cases, or else you need to define four different functions.

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