cell vector array division

Hello,

I have two cell array made of different lengths vectors. Also the arrays have different layouts: 3x3 cells vs. 3x1 cells.

How can I divide them and retain the min vector length to the elements of the newly created array?

I have already tried C=A.\B and seems to be a problem with the cell type of the arrays.

Many thanks.

[David Hill]

Do not understand you. It is not hard to find the array having minimum length within the cell arrays. But I have no idea what this sentence means: How can I divide them and retain the min vector length to the elements of the newly created array.

[Jan]

Please provide some sample data and the wanted output.

[Catalin Dinu]

Hello,

I'm using two different lengths of vectors 4k and 6k for making up the two arrays. I am looking to have a new array made up of the vectors resulted from the division operation with the first 4k elements. I hope it makes more sense now.

[Jan]

You did not mention, what you want as output.

Answer 1

[David Hill]

Lots of assumptions below, but you should be able to adopt the below code for what you want to do.

[r,c]=size(A);
for R=1:r
  for C=1:c
    B{R,C}=A{R,C}(1:4000)./F{R}(1:4000);%I assume you want to divide across the entire row
  end
end

[Catalin Dinu]

Thank you very much, David! It worked.