2D matrix to 3D matrix given index in the 2D matrix col1

Hello, I need to construct a 3D matrix using a 2D matrix.

As an example, take matrix A which is 7x4.

First element of first column (date format) is repeated at most 2 times in all cases.

Am looking for the last 2 elements of each row to finally form layers of 2x2 matrices, one for each date:

A= ...
[735950 1 3 5; 
735951 1 3 5;
735953 1 4 6;
735950 2 1 7;
735951 2 2 8; 
735952 2 5 9;  
735953 2 3 9]

So, in the first case (735950) I need to form a 3D matrix B where the FIRST layer is

B(:,:,1)= ...
[3 5; 
1 7]

Note A is not in ascending order. For this FIRST layer the 1st row of B is in row1 of A, but the 2nd of B row is in row4 of A.

The second case (735951) SECOND layer is

B(:,:,2)= ...
[3 5 ;
2 8]

The third case (735952) since it is only repeated one time, should be ignored

The fourth case (735953) should be the THIRD layer

B(:,:,3)= ...
[4 6 ;
3 9]

Thanks for any suggestions.

Answer 1

[Shoaibur Rahman]

    C = sortrows(A,1);
    indx = 0;
    for k = 1:size(C,1)-1
        if C(k,1) == C(k+1,1)
        indx = indx+1;
        B(:,:,indx) = C(k:k+1,end-1:end);
    end

[Dave]

Thanks, that helps