Finding peaks in data based on certain threshold

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Satej
Satej el 20 de Dic. de 2014
Comentada: Joshua Briggs el 28 de Mzo. de 2017
Hi I have an array [V Data] (Attached data file).The plot is shown below.
I want to detect the # of peaks (3 in this case) which are above a certain threshold (value is = 0.1) I also want to find the points where it crosses the threshold and extract respective values from V
Thanks SATEJ

Respuesta aceptada

Shoaibur Rahman
Shoaibur Rahman el 20 de Dic. de 2014
Editada: Shoaibur Rahman el 20 de Dic. de 2014
Once I had to write a function for this type of problem in on of my projects. Seeing your question here, I have uploaded that file in file exchange:
Just use your +/-TestV as x, Data as y in the function, and threshold as 0.1. Ignore the outputs for minima.
By the way, if you have a closer look at your figure, there are two small peaks in 'left side', one big peak in 'middle', and one smaller peak at the 'right'. So, there will be 4 peaks in total instead of 3. Plot this data in Matlab, and enlarge the figure to verify this observation.
I guess, if you use the linked function findpeaks, the result will be 4 as well. You could also see the x coordinate at which peaks occur, and also the peak values at those points.

Más respuestas (1)

Image Analyst
Image Analyst el 20 de Dic. de 2014
Describe what "detect" means to you. Obviously you threshold:
abovePointOne = v > 0.1;
but then what? What kind of numbers do you want? The length of the stretches above 0.1? The starting points? The count of the number of stretches above 0.1? What????
  6 comentarios
Satej
Satej el 22 de Dic. de 2014
Hi SS - Can you please post your code to the problem above. I thought I had accepted that answer. That code is very useful. Can you please repost it??? My sincere thanks for same
Best Satej
Joshua Briggs
Joshua Briggs el 28 de Mzo. de 2017
Hi I am looking to do something similar to Satej, and IA's description of SS's code sounds like exactly what I need, just wondering if anyone has it, or if SS could please repost it.

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