Change string of text into multiple lines

I have a string of text that needs to be formatted and saved as a txt file. The string is in this format:
,1,1880802442166,1,751702411341,1,751702411358,1,751702411365,1,751702411372,1,751702411389,1,751702459060,1,751702459077,1,751702459084,3,751702459091,1,751702459107,1,751702459114,2,751702459121,1,751702459145...
It needs to be output in this format:
,1,1880802442166
,1,751702411341
,1,751702411358
,1,751702411365
,1,751702411372
,1,751702411389
,1,751702459060
,1,751702459077
,1,751702459084
,3,751702459091
,1,751702459107
,1,751702459114
,2,751702459121
,1,751702459145...
It's for an inventory list that was recorded in the wrong format.
Thanks in advance,
Nick

 Respuesta aceptada

Azzi Abdelmalek
Azzi Abdelmalek el 20 de Dic. de 2014
s=',1,1880802442166,1,751702411341,1,751702411358,1,751702411365,1,751702411372,1,751702411389,1,751702459060,1,751702459077,1,751702459084,3,751702459091,1,751702459107,1,751702459114,2,751702459121,1,751702459145'
a=regexp(s,',','split')
a(1)=[]
b=reshape(a,2,[])'
c=cellfun(@(x,y) [',' x ',' y], b(:,1),b(:,2),'un',0)
fid=fopen('file.txt','w')
for k=1:numel(c)
fprintf(fid,'%s \r\n',c{k,:})
end
fclose(fid)

1 comentario

I needed a blank line between each in value in the list, but I just added an extra
\r\n
in
fprintf(fid,'%s \r\n',c{k,:})
Thanks

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Más respuestas (1)

Andrei Bobrov
Andrei Bobrov el 20 de Dic. de 2014
Editada: Andrei Bobrov el 20 de Dic. de 2014
s = ',1,1880802442166,1,751702411341,1,751702411358,1,751702411365,1,751702411372,1,751702411389,1,751702459060,1,751702459077,1,751702459084,3,751702459091,1,751702459107,1,751702459114,2,751702459121,1,751702459145';
out = mat2cell(s,1,diff([regexp(s,',\d,'),numel(s)+1]))

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Más información sobre Characters and Strings en Centro de ayuda y File Exchange.

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el 20 de Dic. de 2014

Comentada:

el 20 de Dic. de 2014

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