System impulse response and Convolution by matlab
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Hi everyone, i am very new to matlab, and would like to konw how to obtain y(t) from below
Generate a unit step function as the input function, x(t), and an exponentially decay function as the impulse response function, h(t), such as h(t)=exp(-t/2) (note: 2 is the time constant of the system dynamic response). Using MATLAB to calculate the output of the system, y(t).
Thank you so much in advance
2 comentarios
Seikh Rana
el 22 de Abr. de 2018
Convolution (random position zero) in matlab plz help me
Seikh Rana
el 22 de Abr. de 2018
</matlabcentral/answers/uploaded_files/114156/convooooo.JPG> this picture problem solved in matlab plz help me
Respuestas (3)
psyx21
el 29 de Abr. de 2011
1 voto
hey friends what will be the peak acceleration response for 100g 6ms half sine pulse with zeta=0. I need a matlab script with natural frequency on x axis..thanks
Paulo Silva
el 20 de Feb. de 2011
t=0:0.1:10;
u=0*t;
u(t>=0)=1;
h=exp(-t/2);
y=u.*h;
plot(t,y)
8 comentarios
gedaa
el 21 de Feb. de 2011
Paulo Silva
el 21 de Feb. de 2011
it's the same as
u=zeros(size(t))
It creates a variable with the same size as t but full of zeros. I learned that trick here at matlabcentral :)
David Young
el 21 de Feb. de 2011
Paulo - I just wonder if this is right. In the time domain, don't you need to convolve the input and the impulse response rather than multiplying them?
Paulo Silva
el 21 de Feb. de 2011
Yes you are correct, try
t=0:0.1:10;
u=0*t;
u(t>=0)=1;
h=exp(-t/2);
y=conv(u,h);
plot(y)
Paulo Silva
el 21 de Feb. de 2011
Correction for the amplitude and time scale
T=0.1;
t=0:T:10;
u=0*t;
u(t>=0)=1;
h=exp(-t/2);
y=conv(u,h);
plot(t,T*y(1:numel(t)))
gedaa
el 21 de Feb. de 2011
Paulo Silva
el 21 de Feb. de 2011
I'm not sure about the amplitude at
plot(t,T*y(1:numel(t)))
with the step function is good compared to
step(tf([1],[1 1/2])) but with the impulse it's plot(t,y(1:numel(t))) without the T, I can't figure out why that happens.
gedaa
el 23 de Feb. de 2011
Arpan Patel
el 25 de Feb. de 2021
0 votos
t=0:0.1:10;
u=0*t;
u(t>=0)=1;
h=exp(-t/2);
y=u.*h;
plot(t,y)
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