exportgraphics dynamic file name
14 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Pelajar UM
el 22 de Mzo. de 2022
Comentada: Ive J
el 22 de Mzo. de 2022
What's the correct syntax if you want to name the files dynamically when using exportgraphics?
I have a cell array A with 16 titles in each columns that are assigned to the colorbar string. I want to use the same titles to name the files.
for k = 1:16
%rest of the code
c = colorbar;
c.Label.String = string (A (:,k));
exportgraphics(gcf, string (A(:,k)) '.png' ,'Resolution',DPI) %this doesn't work
end
0 comentarios
Respuesta aceptada
Ive J
el 22 de Mzo. de 2022
% A = {'name1', ...}
for k = 1:16
%rest of the code
c = colorbar;
c.Label.String = A{k};
exportgraphics(gcf, string(A{k}) + ".png" ,'Resolution',DPI) %this doesn't work
end
You could also use strcat, join or similar functions.
10 comentarios
Más respuestas (0)
Ver también
Categorías
Más información sobre Interactive Control and Callbacks en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!