# How can I store the 100 rows of the array in one Matrix?

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M el 1 de Abr. de 2022
Comentada: M el 1 de Abr. de 2022
There is an array X with size (1*3*100)
This is part from array X:
val(:,:,1) =
0 0 0
val(:,:,2) =
-0.0141 -0.0508 0.0786
val(:,:,3) =
0.0067 0.0035 0.0466
val(:,:,4) =
-0.0082 -0.0357 0.1057
.
.
.
.
How can I store the 100 rows of the array in one Matrix?
As the following:
M= [0 0 0
-0.0141 -0.0508 0.0786
0.0067 0.0035 0.0466
-0.0082 -0.0357 0.1057
.
.
.
]
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Stephen23 el 1 de Abr. de 2022
format compact
X = rand(1,3,100)
X =
X(:,:,1) = 0.2610 0.7753 0.1906 X(:,:,2) = 0.4463 0.8890 0.9545 X(:,:,3) = 0.0754 0.2577 0.3922 X(:,:,4) = 0.1844 0.1592 0.2030 X(:,:,5) = 0.5921 0.9162 0.3389 X(:,:,6) = 0.6233 0.7575 0.9247 X(:,:,7) = 0.5424 0.3020 0.0392 X(:,:,8) = 0.0321 0.5100 0.8204 X(:,:,9) = 0.4460 0.4485 0.3025 X(:,:,10) = 0.3534 0.2574 0.9295 X(:,:,11) = 0.9426 0.3157 0.6158 X(:,:,12) = 0.1833 0.0886 0.0745 X(:,:,13) = 0.1382 0.4573 0.6580 X(:,:,14) = 0.3467 0.4151 0.8104 X(:,:,15) = 0.6849 0.5989 0.2851 X(:,:,16) = 0.2252 0.8867 0.4931 X(:,:,17) = 0.9749 0.6078 0.3188 X(:,:,18) = 0.2712 0.3518 0.3717 X(:,:,19) = 0.7859 0.6830 0.5968 X(:,:,20) = 0.0304 0.5481 0.4461 X(:,:,21) = 0.1388 0.9546 0.5119 X(:,:,22) = 0.9788 0.5397 0.4085 X(:,:,23) = 0.7342 0.0590 0.6495 X(:,:,24) = 0.0670 0.0458 0.8988 X(:,:,25) = 0.6265 0.9745 0.9822 X(:,:,26) = 0.3195 0.1942 0.0645 X(:,:,27) = 0.6318 0.4194 0.0178 X(:,:,28) = 0.1456 0.0349 0.9779 X(:,:,29) = 0.8615 0.9460 0.3660 X(:,:,30) = 0.6253 0.6522 0.1224 X(:,:,31) = 0.5275 0.7047 0.5588 X(:,:,32) = 0.1782 0.0553 0.6049 X(:,:,33) = 0.3509 0.7955 0.4287 X(:,:,34) = 0.4076 0.9453 0.5513 X(:,:,35) = 0.5998 0.6466 0.6220 X(:,:,36) = 0.3703 0.5884 0.0190 X(:,:,37) = 0.3498 0.2052 0.3905 X(:,:,38) = 0.7141 0.5986 0.4892 X(:,:,39) = 0.0370 0.6431 0.3851 X(:,:,40) = 0.0538 0.9922 0.0875 X(:,:,41) = 0.8844 0.4010 0.2841 X(:,:,42) = 0.5577 0.5440 0.6333 X(:,:,43) = 0.6519 0.1123 0.8019 X(:,:,44) = 0.7565 0.3836 0.3348 X(:,:,45) = 0.1791 0.2293 0.2110 X(:,:,46) = 0.2157 0.8277 0.6748 X(:,:,47) = 0.5985 0.6912 0.0494 X(:,:,48) = 0.6085 0.7494 0.7303 X(:,:,49) = 0.9907 0.4936 0.5521 X(:,:,50) = 0.1180 0.5213 0.2927 X(:,:,51) = 0.2952 0.1809 0.2030 X(:,:,52) = 0.9577 0.7023 0.3917 X(:,:,53) = 0.8664 0.3853 0.6261 X(:,:,54) = 0.1340 0.5765 0.1492 X(:,:,55) = 0.5226 0.0813 0.0564 X(:,:,56) = 0.2217 0.8792 0.7096 X(:,:,57) = 0.3707 0.4235 0.4360 X(:,:,58) = 0.8633 0.5735 0.1470 X(:,:,59) = 0.2653 0.7682 0.5466 X(:,:,60) = 0.3193 0.5594 0.1601 X(:,:,61) = 0.6760 0.0574 0.3759 X(:,:,62) = 0.0226 0.1508 0.2988 X(:,:,63) = 0.4270 0.5699 0.2162 X(:,:,64) = 0.2079 0.5522 0.1885 X(:,:,65) = 0.6581 0.6746 0.7571 X(:,:,66) = 0.3552 0.0817 0.9710 X(:,:,67) = 0.0206 0.2665 0.7204 X(:,:,68) = 0.6667 0.6415 0.7206 X(:,:,69) = 0.6568 0.6219 0.6664 X(:,:,70) = 0.7361 0.8025 0.5165 X(:,:,71) = 0.3700 0.9351 0.5992 X(:,:,72) = 0.2560 0.7981 0.4384 X(:,:,73) = 0.8505 0.5719 0.8086 X(:,:,74) = 0.1736 0.2363 0.7825 X(:,:,75) = 0.9378 0.8656 0.4070 X(:,:,76) = 0.4563 0.8930 0.3503 X(:,:,77) = 0.1596 0.5364 0.6910 X(:,:,78) = 0.2042 0.0699 0.4360 X(:,:,79) = 0.8038 0.4405 0.4835 X(:,:,80) = 0.1334 0.2420 0.6274 X(:,:,81) = 0.0375 0.9518 0.3643 X(:,:,82) = 0.1320 0.2951 0.5107 X(:,:,83) = 0.2021 0.0310 0.7291 X(:,:,84) = 0.2158 0.1530 0.4583 X(:,:,85) = 0.4505 0.3231 0.4161 X(:,:,86) = 0.9432 0.6858 0.7724 X(:,:,87) = 0.9257 0.7490 0.2286 X(:,:,88) = 0.6480 0.4304 0.8711 X(:,:,89) = 0.1514 0.2978 0.8251 X(:,:,90) = 0.3794 0.5596 0.9140 X(:,:,91) = 0.8523 0.0166 0.5449 X(:,:,92) = 0.2890 0.7142 0.7286 X(:,:,93) = 0.2178 0.4563 0.7055 X(:,:,94) = 0.7325 0.7849 0.3318 X(:,:,95) = 0.6584 0.3747 0.0224 X(:,:,96) = 0.6556 0.8711 0.1207 X(:,:,97) = 0.4160 0.3767 0.8468 X(:,:,98) = 0.8686 0.3400 0.1803 X(:,:,99) = 0.5421 0.5031 0.5253 X(:,:,100) = 0.4931 0.4501 0.4782
Y = permute(X,[3,2,1])
Y = 100×3
0.2610 0.7753 0.1906 0.4463 0.8890 0.9545 0.0754 0.2577 0.3922 0.1844 0.1592 0.2030 0.5921 0.9162 0.3389 0.6233 0.7575 0.9247 0.5424 0.3020 0.0392 0.0321 0.5100 0.8204 0.4460 0.4485 0.3025 0.3534 0.2574 0.9295
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M el 1 de Abr. de 2022
@Stephen Thanks

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