How do I calculate mean absolute error?

x_T = 0.3; y_T = 0.3;
A_T = 38:0.1:45;

for i_A = 1:length(A_T)
   
    for i_file = meas
        error_1(i_file,:) = sqrt((x_T_est1(i_file,:) - x_T).^2 + (y_T_est1(i_file,:) - y_T).^2);
    end
end

Hello everyone. I am sharing part of my code. I am also attaching the necessary files.

What I want to do is adapt this formula. The number n is the size of the matrix x_T_est1 an y_T_est1. So 28x5=140. n = 140.

I want to calculate MAE for all numbers in matrix x_T_est1. But I want to save it in a matrix of length i_A.

In summary, subtract the x_T and y_T values for all the elements in the x_T_est1 matrix, take the square root, and add the value for all the elements. Then divide by 140. This result is a number. For example, let the result be the number A. Let it record this number A as the length of the matrix A_T. So the result vector and the vector A_T will be the same size. Result matris = A, A, A...(1x71). Vector A_T is a vector of length 1x71.

You can change the code however you want.

Answer 1

[David Hill]

x_T = 0.3; y_T = 0.3;
%A_T = 38:0.1:45; have no idea what you are doing with A_T (it is not in your equation)
[x,y]=meshgrid(x_T_est1,y_T_est1);
mae=sum(sqrt((x_T-x).^2+(y_T-y).^2)./numel(x),'all');%this is the mae for the x_T and y_T values listed

[studentmatlaber]

I didn't share the whole code here. However, A_T has a task like this. The matrix x_T_est1 is calculated as much as the number of A_T. So the matrix x_T_est1 is created 71 times. My goal here is to keep the MAE calculated from each different matrix x_T_est1 in a matrix.

When I try your code I get an error like this.

Error using sum
Invalid option. Option must be 'double', 'native', 'default', 'omitnan', or 'includenan'.

[David Hill]

Sorry, try it now.