Help with For loop during least square fit

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Daniel
Daniel el 13 de En. de 2015
Editada: dpb el 14 de En. de 2015
Hello,
I want to linearize my stress-number of cycles plot.
I have my StressAmp and FatigueLife-vectors. The thing I want help with my for-loop.
I want to calculate BTak which is
The sum of when Xi and Yi goes from 1 to the maximum of X and Y.
sum of(Xi-XMean)*(Yi-YMean) / (sum of (Xi-XMean)^2)
It looks like my for loop does not sum BTak, it only gives me the value for each i. What can I do to have each calculated BTak in a vector and add each value?
I know that i have more things to do after calculating BTak, but I am stuck at this Point.
StressAmp=[200 200 200 200 175 175 175 175 150 150 150 150];
FatigueLife=[9.8E3 1.2E4 4.1E4 2.4E4 7.7E6 5.6E5 4.0E6 5.2E6 2.5E7 9E7 4.2E7 3E7];
%Log
X=log10(StressAmp);
Y=log10(FatigueLife);
%Sort X and Y
[StressAmpSortX,i]=sort(X)
FatigueLifeSortY=(Y(i))
%Mean value X and Y
XMean=mean(X);
YMean=mean(Y);
figure
semilogx(FatigueLife,StressAmp,'*');
ylim([100 250])
grid on
for j=[FatigueLifeSortY]
for k=[StressAmpSortX]
BTak=((k-XMean)*(j-YMean))/((k-XMean)^2)
end
end
Thank you.

Respuestas (1)

dpb
dpb el 13 de En. de 2015
>> S=[200 200 200 200 175 175 175 175 150 150 150 150];
F=[9.8E3 1.2E4 4.1E4 2.4E4 7.7E6 5.6E5 4.0E6 5.2E6 2.5E7 9E7 4.2E7 3E7];
>> S=fliplr(S);F=fliplr(F); % same result as sort given S is already ordered decreasing
>> s=(1:N)-mean(log10(S)); % standardized values
>> f=(1:N)-mean(log10(F));
>> BTak=dot(s,f)/dot(s,s)
BTak =
0.4499
>>
To do it with an explicit sum, you need to use a single loop over 1:length(S) and step thru each array and use a subscript in the LHS assignment. But, Matlab's strength is it's builtin functions that do many of these things innately. Of course, remembering the definition of a dot product is a start plus learning that there is a builtin in function for it takes some time or using the help facilities...Matlab has so much available that it can take a while... :)
  2 comentarios
Daniel
Daniel el 13 de En. de 2015
I got s and f to be of different number of columns?... I tried this instead
for i=1:length(StressAmpSortX)
BTak(i)=((StressAmpSortX(i)-XMean)*(FatigueLifeSortY(i)-YMean))/((StressAmpSortX(i)-XMean)^2)
end
BTak=sum(Btak)
and it seems to what I want.
I agree, there are many builtin fuctions, I found out that polyfit just did all my work... Thanks
dpb
dpb el 13 de En. de 2015
Editada: dpb el 14 de En. de 2015
OK, that's a different definition....
NB: that if
SXmean=StressAmpSortX(i)-XMean;
FXmean=FatigueLifeSortY(i)-YMean;
then the summed quantity can be written as
SXmean*FXmean/FXmean^2
which is simply
SXmean/FXmean
Or using shorthand of lowercase s and f to reduce typing at the command line, I get
>> s=StressAmpSortX-XMean;
>> f=FatigueLifeSortY-YMean;
>> dot(1./s,f)
ans =
275.1711
>> sum(BTak)
ans =
275.1711
>>
Again, no loops needed... :)

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