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loop of Column Average

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Arvind Gauns
Arvind Gauns el 19 de Abr. de 2022
Comentada: Arvind Gauns el 19 de Abr. de 2022
I have a matrix of 1024 * 78.(datatype: double )
I want to average every two columns such that the resultant matrix must be 1024*39. (average of every two matrix)
how to get it done?
again for time being if i dont know the number of columns (due to huge dataset) and want to run a loop for averaging the columns for the similar case as mentioned about, what will be the changes in the code ?

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Davide Masiello
Davide Masiello el 19 de Abr. de 2022
Editada: Davide Masiello el 19 de Abr. de 2022
There's no need to use a for loop.
Try the code below.
clear,clc
A = rand(1024,78); % initial matrix of doubles
B = (A(:,1:2:end-1)+A(:,2:2:end))/2; % matrix of averages for each two columns
size(B)
ans = 1×2
1024 39

Más respuestas (1)

Eric Delgado
Eric Delgado el 19 de Abr. de 2022
Hi @Arvind Gauns, just pass your input matrix to the function below. Hope it helps! :)
function outMatrix = Fcn_twoColumnsMean(inMatrix)
arguments
inMatrix (1024,:) {mustBeNumeric} = randn(1024, 78)
end
NN = floor(width(inMatrix)/2);
outMatrix = zeros(1024, NN);
for ii = 1:NN
outMatrix(:,ii) = mean(inMatrix(:,2*ii-1:2*ii), 2);
end
end
  5 comentarios
Eric Delgado
Eric Delgado el 19 de Abr. de 2022
For sure! Especially if the script is becoming too big. So... you have to create modules for debugging purposes. But at the end of the day, it's your call! :)
Arvind Gauns
Arvind Gauns el 19 de Abr. de 2022
in that case i need not need to call the function right ?

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