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Why the responses of the following equations are nothing?

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Marzieh Nodeh
Marzieh Nodeh el 21 de Abr. de 2022
Comentada: Star Strider el 25 de Abr. de 2022
I'm trying to find aeq from the following equations. There are 3 equations with 3 unknowns. but the final response is empty brackets for all unknowns. Could you help me to solve this equation.
Regards,
syms ae gama A
eq1= (23.4255*(ae^3))+(1.2308e-06*ae)+gama
eq2= (A/(6*23.4255))-((2*1.2308e-06)/A)-ae
eq3= A-((((-108*gama)+(12*(sqrt(3*(((4*(1.2308e-06^2))+(27*(gama^2)*23.4255))/23.4255)))))*(23.4255^2)))^(1/3)
eqs= [eq1, eq2, eq3]
[ae,gama,A]=vpasolve(eqs, [ae,gama,A])
%reported results
ae =
[ empty sym ]
gama =
[]
A =
[]

Respuestas (1)

Star Strider
Star Strider el 21 de Abr. de 2022
Use solve then vpa
syms ae gama A
eq1= (23.4255*(ae^3))+(1.2308e-06*ae)+gama
eq1 = 
eq2= (A/(6*23.4255))-((2*1.2308e-06)/A)-ae
eq2 = 
eq3= A-((((-108*gama)+(12*(sqrt(3*(((4*(1.2308e-06^2))+(27*(gama^2)*23.4255))/23.4255)))))*(23.4255^2)))^(1/3)
eq3 = 
eqs= [eq1, eq2, eq3]
eqs = 
[ae,gama,A]=solve(eqs, [ae,gama,A]);
Warning: Possibly spurious solutions.
ae = vpa(ae,7)
ae = 
gama = vpa(gama,7)
gama = 
A = vpa(A,7)
A = 
Also consider double instead of vpa, depending on the result you want.
.
  6 comentarios
Marzieh Nodeh
Marzieh Nodeh el 25 de Abr. de 2022
Perfect. Thank you very much for your help.
Star Strider
Star Strider el 25 de Abr. de 2022
My pleasure!
If my Answer helped you solve your problem, please Accept it!
.

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