How to get a one function result?

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Akash Pal
Akash Pal el 6 de Mayo de 2022
Comentada: Walter Roberson el 9 de Mayo de 2022
I have a main function called mainfun
function [out1,out2]=mainfun(input)
[out1]=fun1(input);
[out2]=fun2(input);
end
so my question is ,may be i am calling my mainfun,and I want to display the individual result from different sub function,but how to display if there is any error in one subfunction ?
like an example ,
if in my fun1 there is eroor then also i want to get the fun2 result .

Respuesta aceptada

Walter Roberson
Walter Roberson el 9 de Mayo de 2022
You can create a helper function
function varargout = safe(fcn, varargin)
try
[varargout{}] = fcn(varargin{:}) ;
catch ME:
varargout(:) = {nan};
end
With that you can
[out1] = safe(@fun1,input);
[out2] = safe(@fun2,input);
  4 comentarios
Akash Pal
Akash Pal el 9 de Mayo de 2022
[F1,M1,deobj1a,bb1,deobj2a,Xa,Coap,Co1ap,combap,obj1ap,obj2ap,comb1ap,comb3ap,comb4ap,comb5ap,comb6ap,comb12ae,obj11ae,obj22ae,comb11ae,comb22ae,comb33ae,comb44ae,comb55ae,comb66ae,t1a,t2a,t4a,t3a,t5a]=safe(@Together2,C,Dij,i,j,Fj,Uij,DQij)
Output argument "varargout{2}" (and maybe others) not assigned during call to "safe".
First i made one extra function called safe ,as guided by you .then i am just calling my subfunction .but its showing this kind or output.
Walter Roberson
Walter Roberson el 9 de Mayo de 2022
function varargout = safe(fcn, varargin)
try
[varargout{1:nargout}] = fcn(varargin{:}) ;
catch ME:
varargout(1:nargout) = {nan};
end

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Más respuestas (1)

David Hill
David Hill el 6 de Mayo de 2022
function [out1,out2]=mainfun(input)
out1=nan;out2=nan;
try [out1]=fun1(input);
end
try [out2]=fun2(input);
end
  2 comentarios
Akash Pal
Akash Pal el 9 de Mayo de 2022
i tried the ..Its helpfull ,incase of lots of output in the both sub function that time what to do ?should i write also
out1=nan;out2=nan ; for every individual output ?
Walter Roberson
Walter Roberson el 9 de Mayo de 2022
You should initialize any output variable that might otherwise not be assigned to because of errors.

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