I need to format a text file
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Duane Melvin
el 24 de Mayo de 2022
Comentada: Voss
el 25 de Mayo de 2022
0.6876 1 0CF02A83x Rx d 8 13 7D 00 7D 29 7D C0 FF
0.6882 1 0CFFD183x Rx d 8 1C DE 8F FE FA BD 8A 42
0.6976 1 0CF02A83x Rx d 8 0B 7D 08 7D 2F 7D C0 FF
0.6982 1 0CFFD183x Rx d 8 2B DE CF FB FA E1 8A 42
0.7076 1 0CF02A83x Rx d 8 FD 7C 0D 7D 29 7D C0 FF
0.7082 1 0CFFD183x Rx d 8 3C DE 8F FC FA AD 8A 42
0.7176 1 0CF02A83x Rx d 8 F9 7C 15 7D 25 7D C0 FF
0.7182 1 0CFFD183x Rx d 8 48 DE 2F FE FA 55 8A 42
This is a .txt file with potentially 500000 rows, only 8 are displayed for my question
I want to write a Matlab script to perform these 5 steps on the .txt file above:
1) remove every row that contains F02A
2) remove these items from the remaining rows 1 0CFFD183x Rx d 8 leaving only the 8 HEX values
3) keep only the first two bytes of the HEX values as in rows 2, 4, 6, 8, want to have only 1C DE remaining
example:
1C DE
2B DE
3C DE
48 DE
5) last step is to convert to Decimal, then perform this math
example for row one (DE*256)+1C)/DE or ((222*256)+28)/222 =
example for row two (DE*256)+2B)/DE or ((222*256)+43)/222 =
which produces this for first and second rows above etc
256.1261
256.1936
.
.
.
Thanks for answering
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Respuesta aceptada
Voss
el 24 de Mayo de 2022
It's not clear whether you need any of those intermediate results or just the final result, but here's one way to do everything:
fid = fopen('test.txt');
data = fread(fid,'*char').';
fclose(fid);
% Steps 1-3
hex_data = regexp(strsplit(data,newline()), ...
'([0-9A-F]+)x\>.*?(\<[0-9A-F]{2}\>)\s(\<[0-9A-F]{2}\>)', ...
'tokens','once');
hex_data = vertcat(hex_data{:})
hex_data(contains(hex_data(:,1),'F02A'),:) = []
% Step 5
result = hex2dec(strcat(hex_data(:,3),hex_data(:,2)))./hex2dec(hex_data(:,3));
disp(result);
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