Subscripted assignment dimension mismatch.

2 visualizaciones (últimos 30 días)
rupal
rupal el 26 de Mayo de 2022
Comentada: rupal el 27 de Mayo de 2022
When I changed the value of C from [0 1] to eye(2) I am getting the following error:
Subscripted assignment dimension mismatch.
Error in set_quasi (line 46)
Phi( (i-1)*nu+1:i*nu, (i-1)*nx+1:i*nx) = Ctid
Please help me to resolve this.
I have attached my code also.
clc
clear
% define model parametres
Kp=3.3; Ao1=0.1781; Ao2=0.1781; At1=15.5179;At2=15.5179; g=981;Le1=15; Le2=15;
Ac=[(-Ao1*sqrt(g/(2*Le1))/At1) 0;(Ao1*sqrt(g/(2*Le2))/At2) (-Ao2*sqrt(g/(2*Le2))/At2)];
Bc=[Kp/At1;0];
Cc=[0 1];
%discrete time model
dt=0.01; %sampling time
sys=ss(Ac,Bc,Cc,0);
ds=c2d(sys,dt);
Ad=ds.a; Bd=ds.b; Cd= ds.c;
N = 9;
u_max = 18;
u_min = 2;
Atid=[Ad zeros(2,1);eye(1) zeros(1,2)];
Btid=[Bd;zeros(1)];
Ctid=[Cd zeros(1)];
% Number of states and control signals
nx = size(Atid,2);
nu = size(Btid,2);
% LQR values
Q_mat =[Ctid'*Ctid];
S = eye(nu);
R = 0.00001;
[~,P,~] = dlqr(Atid,Btid,Q_mat,R);
%% Reference Parameters
% Initilize matrices
% xf = zeros(1:nx)';
xf = [15 15 0]';
% Initilize QP matrices
Psi = zeros(nx*N, nx);
Omega = zeros(nx*N, nu*N);
Phi = zeros(nu*N, nx*N);
H11 = zeros(nu*N,nu*N);
H22 = zeros(nx*N,nx*N);
H33 = zeros(nu*N,nu*N);
H44 = [zeros(nx,nx*(N-1)) eye(nx)];
% Construct QP matrices
for i = 1:N
Psi( (i-1)*nx+1:i*nx, :) = Atid^i;
Phi( (i-1)*nu+1:i*nu, (i-1)*nx+1:i*nx) = Ctid
H11( (i-1)*nu+1:i*nu, (i-1)*nu+1:i*nu) = R;
if i<N
H22( (i-1)*nx+1:i*nx, (i-1)*nx+1:i*nx ) = Q_mat;
H33( (i-1)*nu+1:i*nu, (i-1)*nu+1:i*nu ) = S;
else
H22( (i-1)*nx+1:i*nx, (i-1)*nx+1:i*nx ) = P;
end
for j=1:i
Omega( (i-1)*nx+1:i*nx, (j-1)*nu+1:j*nu ) =[Atid^(i-j)*Btid] ;
end
end
  4 comentarios
Torsten
Torsten el 26 de Mayo de 2022
Phi{i} = Ctid
rupal
rupal el 27 de Mayo de 2022
Thanks for the help .I resolved the issue.

Iniciar sesión para comentar.

Respuestas (0)

Categorías

Más información sobre Programming en Help Center y File Exchange.

Etiquetas

Productos


Versión

R2017a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by