Hello I have a hex cell array and I indexed them.
For example I have 'A7' and when I use hex2dec, it gives me nonsense result which is -7.7452e-121. how can I get exact result? I mean I want to see that hex A7 = decimal 167.
Thank you.

6 comentarios

Chunru
Chunru el 3 de Jun. de 2022
Can you show your cell array?
Rik
Rik el 3 de Jun. de 2022
Please post code that reproduces this issue. You can run code within the editor to make sure the effect matches what you see in your local copy.
tinkyminky93
tinkyminky93 el 3 de Jun. de 2022
My cell array is like
4x1 cell array
{'3A'} {'F1'} {'CF'} {'4C'}
tinkyminky93
tinkyminky93 el 3 de Jun. de 2022
I can not post it there because I am reading these values from data log.
Stephen23
Stephen23 el 3 de Jun. de 2022
Editada: Stephen23 el 3 de Jun. de 2022
hex2dec('A7') % what you should have used
ans = 167
hex2num('A7') % what you actually used
ans = -7.7452e-121
The unfortunately named NUM2HEX and HEX2NUM convert to/from the IEEE 754 floating point hexadecimal representation, they are completely unsuitable for your task. Just for interest, the complete hexadecimal is:
num2hex(hex2num('A7'))
ans = 'a700000000000000'
Apparently someone thought that it would be a good idea to pad its input with trailing zeros. Ugh.
Chunru
Chunru el 3 de Jun. de 2022
Editada: Chunru el 3 de Jun. de 2022
hex2num inteprete 'A7' as IEEE double number (64bit) with mantissa and exponents. So padding 0's before 'A7'. The string is in a different order (from last byte to first byte) so it looks like (actually not) padding 0's after 'A7'.

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Chunru
Chunru el 3 de Jun. de 2022
x ={'3A', 'F1', 'CF', '4C'}
x = 1×4 cell array
{'3A'} {'F1'} {'CF'} {'4C'}
y = cellfun(@hex2dec, x)
y = 1×4
58 241 207 76

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el 3 de Jun. de 2022

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