Find the length of a vector up to a certain value
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    Holmbrero
 el 7 de Jun. de 2022
  
    
    
    
    
    Comentada: Holmbrero
 el 8 de Jun. de 2022
            Hi! 
I have a vector (SortN1250) which is 75558x1 with a range from 1:1000 and i want to extract the length of the vector at certain values (100:100:5000) and ad them to another vector. This is my code:
ProbdistPoredens(50,1)=zeros
for n=100:100:5000
    ind = find(abs(SortB1250(:,1)<n));
    lengthind=length(ind)
    for i=1:50
        ProbdistPoredens(i,1)=lengthind
    end
end
ProbdistPoredens is however just filled with the number 75558 on all 50 rows. This number is only expeted to show at the very last row in the column.
Any suggestions would be greatly appriciated! 
Regards,
2 comentarios
Respuesta aceptada
  Image Analyst
      
      
 el 7 de Jun. de 2022
        Explain in words what this means:  (100:100:5000)
Do you want only elements that have values of 100, 200, 300, 400, ..., 4900, or 5000?
Is that what "at certain values" means?  Or does it mean at certain indexes?
3 comentarios
  Image Analyst
      
      
 el 8 de Jun. de 2022
				Try this:
% Create sample data.
SortB1250 = 1000 * rand(75558, 1);
ProbdistPoredens=zeros(50,1);
n = 100 : 100 : 5000
for k = 1 : length(n)
    ind = find(SortB1250 < n(k));
    ProbdistPoredens(k) = length(ind);
end
plot(ProbdistPoredens, 'b.-', 'lineWidth', 2)
grid on;
Más respuestas (1)
  Simon Chan
      
 el 8 de Jun. de 2022
        The inner for loop is not necessary and it overwrite itself for every 'n'.
You may modify the code as follows.
ProbdistPoredens(50,1)=zeros;
for n=100:100:5000
    ind = find(abs(SortB1250(:,1)<n));
    lengthind=length(ind);
    ProbdistPoredens(n/100,1)=lengthind;                % modify the index from i to n/100
end
 Alternatively, you can use function histcounts to do the same thing.
[ProbdistPoredens,~] = histcounts(SortB1250,0:100:5000,'Normalization','cumcount')   % Use function hiscounts
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