(Matrix Optimization) Optimization method for coefficient matrix in Ax = b with known x and b.
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    Nipun Vashistha
 el 12 de Jun. de 2022
  
    
    
    
    
    Comentada: Nipun Vashistha
 el 12 de Jun. de 2022
            Hi,
I have two 4*1 data vectors x and b which represents meaured 'Intensity vector' and 'Stokes vector'. These two vectors are related to each other by a 4*4 transfer matrix A as Ax = b. In the ideal case, the relationship for all x and b must satisfy Ax = b for an ideal transfer matrix A_ideal = [0.5 0.5 0 0;0.5 0 0.5 0;0.5 -0.5 0 0;0.5 0 -0.5 0]. 
Now, in a non-ideal system I want to predict the matrix A for some x and b which will satisfy Ax = b. In the optimization routine A can be initialized as A_ideal and will optimize after each iteration until Ax = b is satified (or we get an near approximation).
What is the best method to optimization the above matrix and how can I implement it? 
Thank you!
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Respuesta aceptada
  Torsten
      
      
 el 12 de Jun. de 2022
        If x1, b1, x2, b2 are your given data, use
x1 = [2 7 56 -3];
b1 = [12 -4 0.23 pi];
x2 = [-5 23 9.5 12];
b2 = [0.43 2.4 -12.67 exp(2)];
n = 4;
M = [x1,zeros(1,n),zeros(1,n),zeros(1,n);...
     zeros(1,n),x1,zeros(1,n),zeros(1,n);...
     zeros(1,n),zeros(1,n),x1,zeros(1,n);...
     zeros(1,n),zeros(1,n),zeros(1,n),x1;...
     x2,zeros(1,n),zeros(1,n),zeros(1,n);...
     zeros(1,n),x2,zeros(1,n),zeros(1,n);...
     zeros(1,n),zeros(1,n),x2,zeros(1,n);...
     zeros(1,n),zeros(1,n),zeros(1,n),x2];
R = [b1.';b2.'];
A = lsqlin(M,R);
norm(M*A-R)
A = reshape(A,n,n).'
A*x1.'-b1.'
A*x2.'-b2.'
Más respuestas (1)
  Torsten
      
      
 el 12 de Jun. de 2022
        If you have two 4x1 data vectors x and b to estimate A, you have 8 equations in 16 unknowns.
This system is underdetermined - you can imagine that in general, there are infinitely many ways how A can be chosen.
Is this ok for you ? Or are there some restrictions on the elments of A that should be incorporated ?
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