have been practicing questions i see online i just cant get how to solve this mathwork

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Write a function called flip_it that has one input argument, a row vector v , and one output argument, a row vector w that is of the same length as v. The vector w contains all the elements of v, but in the exact opposite order. For example, if v is equal to [1 2 3] then w must be equal to [3 2 1]. You are not allowed to use the built-in function flip, fliplr, or flipud.
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DGM
DGM el 15 de Jun. de 2022
I will note that they didn't explicitly say you couldn't use flipdim().
But I suppose that's not good enough.
Consider a vector
v = [12 35 48 63];
it has the linear indices:
idx = 1:numel(v);
Suppose you did this instead:
idxr = numel(v):-1:1;
What would happen if you used those indices to address v?
Sam Chak
Sam Chak el 15 de Jun. de 2022
Do you think that sort is easier for you to rearrange the elements?
sort()

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Chandrika
Chandrika el 17 de Jun. de 2022
As per my understanding, you need to code for a function that reverses a vector. You can do this using a recursive function. Please try the following code:
function w=flip_it(v)
w=[];
if isequal(length(v),1)
w=v(1);
elseif length(v) > 1
st=v(1:ceil(length(v)/2));
ed=v(ceil(length(v)/2)+1:end);
w=[flip_it(ed) flip_it(st)];
else
return
end
end
Here, recursion stops when length of the vector is 1, else flip_it function keeps getting called as part of the recursion.

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