find the point of intersection of one curve with itselfs

hey Everyone,

i have:

x = [2 0 0 2 2 -1]';

y = [4 4 0 0 2 2]';

and i have to to find the point, where the function cuts itselfs. I know it should work with cscvn and anonymous function but i dont know how exactly. A picture of the function is attached

Answer 1

[Kevin Holly]

x = [2 0 0 2 2 -1];
y = [4 4 0 0 2 2];

points = [x;y];
h=fnplt(cscvn(points)); 
plot(h(1,:),h(2,:));hold on,
plot(points(1,:),points(2,:),'o'), hold off

I divided the line into two separate lines and used polyxpoly from the mapping toolbox:

[yi,xi] = polyxpoly(h(2,1:round(end/2)-1),h(1,1:round(end/2)-1),h(2,round(end/2):end),h(1,round(end/2):end))

yi = 2.1028

xi = -0.5395

hold on
plot(xi,yi,'g*')

xi

xi = -0.5395

yi

yi = 2.1028