# I have to store 3 sets of data, with for statement

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Devesh Kumar el 21 de Jun. de 2022
Comentada: Devesh Kumar el 28 de Jun. de 2022
for i = 1:cf_n
x1(i,1) = [2 Vr_on_cf Vr_R1_cf(i) Vr_R2_cf(i) Vr_cf_end]; % Az/D for cross - flow
y1(i,1) = [0 0.15 Az1_D(i) Az2_D(i) 0]; % reduced velocity
end
Here Vr_on_cf,Vr_cf_end is constant = 2.5 and 16 respectivetly , Vr_R1_cf & Vr_R2_cf are vector which contains 3 values say [ a b c] and [d e f], in this particular case cf_n is 3
now I want my output like this
x = [2 2.5 a d 16; 2 2.5 b e 16; 2 2.5 c f 16]; basically 5*3 matrix
how should I run the for loop
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Walter Roberson el 21 de Jun. de 2022
for i = 1:cf_n
x1(i,:) = [2 Vr_on_cf Vr_R1_cf(i) Vr_R2_cf(i) Vr_cf_end]; % Az/D for cross - flow
y1(i,:) = [0 0.15 Az1_D(i) Az2_D(i) 0]; % reduced velocity
end
Devesh Kumar el 21 de Jun. de 2022
Thanks allot @Walter Roberson

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Pooja Kumari el 28 de Jun. de 2022
Dear Devesh,
It is my understanding that you want to store three sets of data using for loop.
Given that Vr_on_cf, Vr_cf_end is constant = 2.5 and 16 respectively, Vr_R1_cf & Vr_R2_cf are vector which contains 3 values say [ a b c] and [d e f], in this particular case cf_n is 3.
You can get the provided output using the following code:
Vr_on_cf = 2.5;
Vr_cf_end = 16;
Vr_R1_cf = [ "a" "b" "c"];
Vr_R2_cf = [ "d" "e" "f"];
% x = [2 2.5 a d 16; 2 2.5 b e 16; 2 2.5 c f 16]; %Required Output
for i = 1:3
x1(i,:) = [2 Vr_on_cf Vr_R1_cf(i) Vr_R2_cf(i) Vr_cf_end] % instead of your provided code, you can use this changed to get the required output
end
Sincerely,
Pooja Kumari
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Devesh Kumar el 28 de Jun. de 2022

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