# use of fluid property tables generated with twoPhaseFluidTables directly in Matlab

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Jonathan SH on 23 Jun 2022
Commented: Jonathan SH on 12 Jul 2022
Hi, is it possible to use the two-phase fluid properties table directly in matlab?
For example given a pressure and a temperature find the corresponding internal energy. For this it should be possible to interpolate the values into the temperature/pressure matrix and then interpolate into the internal energy vector.
My goal is to be able to configure a heat pump that I am designing in Simscape fluids.
The properties of the two-phase fluid table are stored in a structure, as shown in the following link:

Yifeng Tang on 29 Jun 2022
Yes, it's possible. The properties you get in the data struct are either functions of pressure, or functions of pressure and normalized energy (unorm). You may find the information about the dimensions of each property matrix here:
Now, you'll need a way to find unorm for the given P & T, and then look up u for the given P & unorm. Try this code:
% specified temperature and pressure
T = 60 + 273.15; % K
P = 0.300; % MPa
% build a p-unorm mesh for 2D lookup
[Xv,Yv] = meshgrid(r134aPropertyTables.p,r134aPropertyTables.vapor.unorm);
% look up temperature at each unorm point at the given pressure
Tvec = interp2(Xv,Yv,r134aPropertyTables.vapor.T,P,r134aPropertyTables.vapor.unorm); % K
% look up unorm at the given T
unorm = interp1(Tvec,r134aPropertyTables.vapor.unorm,T);
% look up u at the given P and the looked-up unorm (for given T)
u = interp2(Xv,Yv,r134aPropertyTables.vapor.u,P,unorm) % kJ/kg
u = 426.5096
This works for vapor. The code for liquid would be very similar. It'll be a good idea to write something to tell if the given P,T is vapor or liquid first. Mixture would be a bit different.
You can first find the saturation properties (unorm=0 and unorm=1) at given pressure, then use the vapor quality to calculate the mixture property.
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Jonathan SH on 12 Jul 2022

R2022a

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