find the minimum value

i need to find which LD(:,6) is min for example min of LD(:,6) between Z2(14)&Z2(2) is 70Km then i need to sumZ2(2) with Z(1) but im confused here

tic
clc
clear all
% -------------------------------Input Data--------------------------------
% Line characeteristics
%        bus   R    line      X      km
LD   = [1  2   0.004  1   0.05i     100
    1  3   0.0057 2   0.0714i   70
    3  4   0.005  3   0.0563i   80
    4  5   0.005  4   0.045i    100
    5  6   0.0045 5   0.0409i   110
    2  6   0.0044 6   0.05i     90
    1  6   0.005  7   0.05i     100];

%Relay 1  2   3  ...
CTR= [240 240 160 240 240 240 160 240 160 240 240 240 240 160];
% a = Angle(45);
PTR= 150e3/110;
%----------------------------- zone (1) ----------------------------------%
for k = 1 : 2
    for b=1:7
        z(b,1)=(LD(b,3)+LD(b,5))*LD(b,6);
        theta(b,1) = angle(z(b,1));
        z = abs(z);
    end
end
z=repmat(z,2,1);
theta=repmat(theta,2,1);
for b= 1:14
    zsz1(1,b) = (0.8*(z(b,1))/(cos((theta(b,1)-45)*pi/180))*(CTR(1,b)/PTR));
end
%----------------------------- zone (2) ----------------------------------%
Z=zsz1*1.25;       %100 Percentage of Line
Z=Z'
Z2=Z/2             %50 Percentage Line
Z3=[Z(1)+min(Z2(14),Z2(2))]   %this line is wrong i need to find which LD(:,6) is min for example min of LD(:,6) between Z2(14)&Z2(2) is 70Km
toc

[Image Analyst]

"but im confused here" <== you're not the only one. 🤨

You say "i need to find which LD(:,6) is min" so why can't you just do

[minValue, indexOfMinValuke] = min(LD(:, 6);

[arian hoseini]

first i calculated Z and Z2 now i need to find which LD is min for (Z2(14),Z2(2)) but u are calculating min LD for the whole column....LD for Z2(14) is 100Km and for Z2(2) is 70Km so Z2(2) is min here after that i need to calculate Z3