how to range data and find maximum value for each range by using loop

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I have data (AB) consisting of two columns. The number of rows of this data is 80315. I want to divide this number into (1: 2000: 80315) and take the maximum values for each period (based on the second column, also i want to index the firt colum).
I using this code but its very long.
a = AB([1:2000],:);
aa=max(a);
a1 = AB([2000:4000],:);
aa1=max(a1);
a11 = AB([4000:6000],:);
aa11=max(a11);
maxvalues=([aa;aa1;aa11])
  2 comentarios
abdullah al-dulaimi
abdullah al-dulaimi el 29 de Jun. de 2022
i mean the output will be 2 coluoms not 1

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Pooja Kumari
Pooja Kumari el 29 de Jun. de 2022
Editada: Pooja Kumari el 29 de Jun. de 2022
It is my understanding that you are facing issues with huge vector and instead of hardcoding, you want a generalized form of code for taking the maximum value for your data for each period by taking 2000 data at a time out of 80315 rows of data.
Please find below an example code for the same with random dataset of 80315 rows and 2 columns:
data = rand(80315,2); %data
index = 1;
for i = 1:1999:80315-1999
array_data = data(i:i+1999,:); %data is divided into %2000 samples at a time.
output(index,1) = max(array_data(:)); %taking max of all values in a period
index = index +1;
end
For more information on array indexing, you can refer to the below link:
Sincerely,
Pooja Kumari
  1 comentario
abdullah al-dulaimi
abdullah al-dulaimi el 29 de Jun. de 2022
dear Pooja Kumari ,
Thank you for your kind efforts.
best regard

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