# Selecting one channel out of many wireless channel based on max channel gain?

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Chetan Fadnis el 4 de Jul. de 2022
Respondida: Muskan el 5 de Sept. de 2023
Sir,
I have following code for selecting one channel out of 5 channels.
C0=10^-3; %path loss at refrence distance 1m.
K1=5; %devices in Group-1
d1=[8.5 9 8.0 9.5 10]; %set of all longest distances (d1>8) between HAP-WD in group-1
%d1 = 8 + (12-8).*rand(K1,1); %set of all longest distances between HAP-WD in group-1
n1=2+(4-2).*rand(K1,1); %path loss exponent between (2 and 4)
L1=C0.*(d1).^-n1; %Path-loss model HAP-WD in group-1
rng(0,'twister');
hhw1=max(sqrt(L1/2).*(randn(K1,1)+1i*randn(K1,1))); % HAP-WD group 1 K1*1 , max channel
this hhw1 produces 1*5 matrix, I have to chose only one out of these five values based on the maximum gain, How can I write this code in more efficient manner. Also how I can make d1 distance to be a random quantity but greator than 8 (One way which is commented is correct?)?
Thanks in anticipation.
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Muskan el 5 de Sept. de 2023
Hi Chetan,
As per my understanding of the question, for making the distance “d1” to be a random quantity but greater than 8, the commented code given by you is correct.
For choosing only one out of these five values based on the maximum gain, you can try the following:
C0 = 10^-3;
K1 = 5;
d1 = 8 + (12-8).*rand(K1,1);
d1n1 = 2 + (4-2).*rand(K1,1);
L1 = C0.*(d1).^-n1;
rng(0,'twister');
hhw1 = (sqrt(L1/2).*(randn(K1,1)+1i*randn(K1,1)));
disp(hhw1) ;
[~, maxIndex] = max(hhw1);
selectedChannel = hhw1(maxIndex);
disp(selectedChannel);
In this modified code, the “max” function is used to find the maximum gain in the “hhw1” matrix. The “maxIndex” variable stores the index of the maximum gain, and the “selectedChannel” variable selects the channel with the maximum gain.
I hope the above information helps resolve your query.
Thanks
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