Plotting Image intensity from Matrix

Greetings to all ! I have a 3D matrix which represnts a Sheep_Logan Phantom. Is there any way to plot the intensity ogf the image matrix both in horizontal and vertical direction? I can do the same things with saving an image but I want it from the matrix that I have attached.

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Image Analyst
Image Analyst el 11 de Jul. de 2022
Do you want the profile along some certain row or columns, like
rowProfile = squeeze(image3d(rowNumber, :, sliceNumber));
columnProfile = squeeze(image3d(:, colNumber, sliceNumber));
or do you want the average profile across the entire plane? Or the max projection? Have you seen slice?

5 comentarios

Amit Chakraborty
Amit Chakraborty el 11 de Jul. de 2022
Editada: Amit Chakraborty el 11 de Jul. de 2022
@Image Analyst, Thank you for your reply. Yes I want the Intensity profile along some certain row or columns ( for a specific slice) for a specific direction (Horizontal/Vertical).
It should be 2D plot ( Having the shape of Gaussing Bell). Kind of Following.
Image Analyst
Image Analyst el 11 de Jul. de 2022
OK, but did my code not work? Did you even try it? It should produce a 1-D plot of the gray scale, like you showed. If you want a 2-D profile, then that is an image and you'd replace one of the number variables by a colon.
Amit Chakraborty
Amit Chakraborty el 11 de Jul. de 2022
Editada: Amit Chakraborty el 11 de Jul. de 2022
@Image Analyst, Thank you so much for helping this novice. your code is perfectly fine.
Another thing for my own knowledge:
How I do them : average profile across the entire plane and the max projection ?
I would first get the entire plane as a 2-D image and then use max for the direction you want. For example
image2d = randi(255, 5, 4)
image2d = 5×4
135 151 116 211 98 187 192 160 112 179 167 117 107 77 125 114 35 113 144 28
verticalMaxProjection = max(image2d, [], 2)
verticalMaxProjection = 5×1
211 192 179 125 144
horizontalMaxProjection = max(image2d, [], 1)
horizontalMaxProjection = 1×4
135 187 192 211
Amit Chakraborty
Amit Chakraborty el 12 de Jul. de 2022
@Image Analyst Thank you SO MUCH !!!!!!

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